各位~我很菜。帮帮我啊~~~

[fly_higher]

给定一字母，要求打印出一个菱形，该菱形中间一行由此字母组成，其相邻的上下两行由它直接前趋字母组成。按此规律，真到字母A出现在第一行和最后一行为止。
如： A
BBB
CCCCC →给定字母C
BBB
A
读入任一含加、减运算的表达式并计算值。其中数为整数，每一数前有一字符，表达式用“=”结束，如输入：+20-4-5+168=

[dudu妈]

#include <iostream>
#include <stdlib.h>

using namespace std;

int main(int argc, char *argv[])
{
static char d[][5]={{' ',' ','A',' ',' '},{' ','B','B','B',' '},{'C','C','C','C','C'},{' ','D','D','D',' '},{' ',' ','E',' ',' '}};
int i,j;
for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
cout<<d[i][j];
cout<<endl;
}
system("PAUSE");
return 0;
}

[dudu妈]

很苯得办法

[fly_higher]

有没有搞错啊~
题目不是这样~

[dean7411]

main()
int a,b,i;
for (a=3,b=1;a>1;a--,b++)
for (i=1;i<a;i++)
printf(" ");
for (i=b;i>1;i--)
printf("%c",a+b);

printf("/n");
写了一半，可能有些错，但思想是这样的，给你借鉴一下

[dean7411]

下一半你自己写吧

[dean7411]

第二题代码量会很多，

[fly_higher]

谢谢楼上的大哥啦~

[dean7411]

修改一下：
#include "stdio.h"
main()
{
int a,b,i;
for (a=3,b=1;a>1;a--,b++)
{
for (i=1;i<a;i++)
printf(" ");
for (i=b;i>1;i--)
printf("%c",a+b);

printf("/n");
}
......
写了一半，可能有些错，但思想是这样的，给你借鉴一下,看懂了上半段你应该可以写出下半段

[seasy]

char ch_out = 'a', ch_in;
int i,j;
int num = ch_in - ch_out;

for(j=num, j>=0; j--)
{
for(i=0; i<j; i++)
{
printf(" ");
}
printf("%c\n", ch_out++);
}

for(j=num, j>=0; j--)
{
for(i=j; i>=0; i--)
{
printf(" ");
}
printf("%c\n", --ch_in);
}

大概就这样吧

[seasy]

第二题有个帖子刚讨论过

[huanmm]

main()
{
printf(" A \n");
printf(" BBB \n");
printf("CCCCC\n");
printf(" BBB \n");
printf(" A \n");
}

[Michael_555]

第一个问题，在VC上调试通过。

#include <stdio.h>

void main()
{
char baseLetter, ch = 'A';
int count, i, m, j;

printf( "Please Input A Letter:" );
scanf( "%c", &baseLetter );

/* check the input character */
while( baseLetter < 'A'
|| baseLetter > 'z'
|| ( baseLetter > 'Z' && baseLetter < 'a' ) )
{
printf( "Input Error!\n" );
printf( "Please Input A Letter:" );
scanf( "%c", &baseLetter );
}

if( baseLetter >= 'a' && baseLetter <= 'z' )
{
baseLetter = baseLetter - ( 'a' - 'A' );
}

m = baseLetter - 'A' + 1;
count = 2 * ( baseLetter - 'A' ) + 1;

for( i = 1; i <= count ; i ++ )
{
for( j = 1; j <= count; j ++ )
{
if( j < m )
{
if( j < baseLetter - ch +1 )
{
printf( " " );
}
else
{
printf( "%c", ch );
}
}
else
{
if( ( count - j ) >= ( baseLetter - ch ) )
{
printf( "%c", ch );
}
else
{
printf( " " );
}
}
}

if( i >= m )
{
ch--;
}
else
{
ch++;
}

printf( "\n" );

}

while( getchar() != '5' ); // input 5 to exit.

}

[Michael_555]

读入任一含加、减运算的表达式并计算值。其中数为整数，每一数前有一字符，表达式用“=”结束，如输入：+20-4-5+168=



#include <stdio.h>
#include <math.h>

int GetNumber( char *paramStr );
int mergeOperAndNum( char oper, int num );
int CalculateTwoNum( int n, int m, char operation );

void main()
{
char str[50];
char oper;
int val=0;
int num1, num2;

printf( "Please Input: ");
scanf( "%s", str );

printf( "You Input String: %s", str );

oper = *str;
str++;

num1 = GetNumber( str );
num1 = mergeOperAndNum( oper, num1 );

while( *str != '=' )
{
oper = *str;
str++;

num2 = GetNumber( str );
val = CalculateTwoNum( num1, num2, oper );
}

printf( "%d\n", val );

while( getchar() != Q ); //input Q to exit

}

int GetNumber( char *paramStr )
{
int value;

while ( *str >= '1' && *str <= '9' )
{
value = ( 10 * *value + ( *str++ - '0' ) ) & 0xFFFF;
}

return value;
}

int mergeOperAndNum( char oper, int num )
{
if( oper == '+' )
{
return num;
}
else if( oper == '-' )
{
num = num - 2 * num;
return num;
}
else
{
printf( "Error1!\n");
return 0xFFFF;
}
}


int CalculateTwoNum( int n, int m, char operation )
{
switch( operation )
{
case '+':
return ( n + m );
case '-':
return ( n - m );
case '*'
return ( n * m );
case '/'
return ( n / m );
default:
printf( "Error2!\n");
return 0xFFFF;
}

}

[Michael_555]

不好意思，要修修


#include <stdio.h>
#include <math.h>

int GetNumber( char *paramStr );
int mergeOperAndNum( char oper, int num );
int CalculateTwoNum( int n, int m, char operation );

void main()
{
char str[50];
char oper;
int val=0;
int num1, num2;

printf( "Please Input: ");
scanf( "%s", str );

printf( "You Input String: %s", str );

oper = *str;
str++;

num1 = GetNumber( str );
num1 = mergeOperAndNum( oper, num1 );

while( *str != '=' )
{
oper = *str;
str++;

num2 = GetNumber( str );
val = CalculateTwoNum( num1, num2, oper );
}

printf( "%d\n", val );

while( getchar() != Q ); //input Q to exit

}

int GetNumber( char *paramStr )
{
int value;

while ( *str >= '1' && *str <= '9' )
{
value = ( 10 * value + ( *str++ - '0' ) ) & 0xFFFF;
}

return value;
}

int mergeOperAndNum( char oper, int num )
{
if( oper == '+' )
{
return num;
}
else if( oper == '-' )
{
num = num - 2 * num;
return num;
}
else
{
printf( "Error1!\n");
return 0xFFFF;
}
}


int CalculateTwoNum( int n, int m, char operation )
{
switch( operation )
{
case '+':
return ( n + m );
case '-':
return ( n - m );
case '*'
return ( n * m );
case '/'
return ( n / m );
default:
printf( "Error2!\n");
return 0xFFFF;
}

}

[fly_higher]

哇~~ 楼上这位强！
不过咧~ 我就是有点地方看不懂哦~ 能否详解~