如何获得请求的url？

[learnner]

比如一个表单提交到我这个servlet,我在这个servlet上如何取得这个表单所在的url?

[tom2005]

request.getRequestURI()
是不是这个

[yellowwee]

StringBuffer sb = javax.servlet.HttpServletRequest.getRequestURL();

[yellowwee]

getRequestURI

public java.lang.String getRequestURI()Returns the part of this request's URL from the protocol name up to the query string in the first line of the HTTP request. The web container does not decode this String. For example:

First line of HTTP request Returned Value
POST /some/path.html HTTP/1.1 /some/path.html
GET http://foo.bar/a.html HTTP/1.0 /a.html
HEAD /xyz?a=b HTTP/1.1 /xyz

To reconstruct an URL with a scheme and host, use HttpUtils.getRequestURL(javax.servlet.http.HttpServletRequest).




是javax.servlet.http.HttpServletRequest，我写少了~

[zhkchi]

getRequestURL()

[learnner]

getRequestURL 和 getRequestURI 好像取得的都是被请求的URL啊

[alpha15]

在前一个页面get出来再set
然后在这个页面再get前面那个页面set的?
呵呵,方法有点笨

[pigo]

取 request.getHeader("referer");