這個正則表達式怎麼寫

[Relta]

Dim mc As MatchCollection
Dim r As New Regex("<ab>.*</ab>", RegexOptions.Compiled)
mc = r.Matches("<ab>.....</ab><ab>...</ab><ab>.........</ab>")
Dim i As Integer
MsgBox(mc.Item(0).Value)

'上面代碼中的....表示一些不規則的字串
'我的顯示結果是："<ab>.....</ab><ab>...</ab><ab>.........</ab>"
'我實際需要的結果：<ab>.....</ab>
這個表達式該如何寫呢?

[haoztao]

<ab>.*</ab>这个表达式是正确，是不是matches的问题？我正则表达式也是刚会用，呵呵。

[Relta]

現在：mc.count顯示為1，我想要的結果應該是3

[E0888]

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[Relta]

up

[landlordh]

:
Dim mc As MatchCollection
Dim r As New Regex("<ab>?[^<ab>]*</ab>", RegexOptions.Singleline)
mc = r.Matches("<ab>.....</ab><ab>...</ab><ab>.........</ab>")
Dim i As Integer
Dim m As Match = r.Match("<ab>.....</ab><ab>...</ab><ab>.........</ab>")

MsgBox(mc.Item(0).Value)

[landlordh]

改进一下：
Dim str1 As String = "<ab>?[^<ab>]*</ab>"
Dim str2 As String = "<ab>.....</ab><ab>...</ab><ab>.........</ab>"
Dim r As New Regex(str1)
Dim mc As MatchCollection = r.Matches(str2)
Dim m As Match = r.Match(str2)
Dim i As Integer = 0
For Each m In mc
MsgBox(mc.Item(i).Value)
i += 1
Next

[landlordh]

<C1DataColumn>.*?[^<C1DataColumn>].*?</C1DataColumn>

[saucer]

try

"<ab>.*?</ab>"

[landlordh]

对呀，这样更好，我想得太多了，让紧跟其后是</..>就行了，

呵呵，长一智

[Relta]

'這樣就不可以了

Dim str1 As String = "<C1DataColumn>?[^<C1DataColumn>]*</C1DataColumn>"
Dim str2 As String = "<C1DataColumn> Level=""0"" Caption=""USERID"" DataField=""USERID""><ValueItems /><GroupInfo /></C1DataColumn><C1DataColumn> Level=""0"" Caption=""USERNAME"" DataField=""USERNAME""><ValueItems /><GroupInfo /></C1DataColumn><C1DataColumn> Level=""0"" Caption=""PASSWORD"" DataField=""PASSWORD""><ValueItems /><GroupInfo /></C1DataColumn>"
Dim r As New Regex(str1)
Dim mc As MatchCollection = r.Matches(str2)
Dim m As Match = r.Match(str2)
Dim i As Integer = 0
'MsgBox(mc.Count)
For Each m In mc
MsgBox(mc.Item(i).Value)
i += 1
Next

[Relta]

up

[Relta]

急啊！