最小公倍数-----

[2006黄晓磊]

def lcm(x, y):
    a = x
    b = y
    while y:
        x,y = y, x % y
    return a * b // x
while True:
    num = input('请输入自然数，以空格分隔:').split()
    LCM = int(num[0])
    for i in range(len(num)):
        if i+1 == len(num):
            break
        LCM = lcm(LCM,int(num[i+1]))
    print('最小公倍数为:%d' % LCM)