实现方法:
SQL> create table a (
2 bm char(4), --编码
3 mc varchar2(20) --名称
4 )
5 /
表已建立.
SQL> insert into a values('1111','1111');
SQL> insert into a values('1112','1111');
SQL> insert into a values('1113','1111');
SQL> insert into a values('1114','1111');
select count(*),anlknz from anl group by anlknz having count(*) > 1;
如果要查看全部数据则:
select * from anl a where exists (select count(*),anlknz from anl b where a.anlknz = b.anlknz having count(*) > 1);