获取Sql Server表索引

lotto 2005-02-18 07:05:21
要做个管理Sql Server表信息的工具,获取表信息已经不成问题了,从Infomartion_Schma里获取,但索引信息难获取,论坛上已有此类问题,但不能解决我的问题,我要获取的是如下信息:
表XXX
主键:
名称:PK_XXX
字段:Fieldname1,FieldName2
索引:
名称:IDX_XXX_123
字段:FieldName3,FieldName4

不知道从系统那几个表里怎样把这个信息搞出来,就象Sql Server自己形成建表脚本一样。
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Softlee81307 2005-02-19
sp_helpindex employee
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didoleo 2005-02-19
上面的邹建有新的版本,里面有索引信息 
SELECT
表名=case when a.colorder=1 then d.name else '' end,
表说明=case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序号=a.colorder,
字段名=a.name,
标识=case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
主键=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid
))) then '√' else '' end,
类型=b.name,
占用字节数=a.length,
长度=COLUMNPROPERTY(a.id,a.name,'PRECISION'),
小数位数=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
允许空=case when a.isnullable=1 then '√'else '' end,
默认值=isnull(e.text,''),
字段说明=isnull(g.[value],''),
索引名称=isnull(h.索引名称,''),
索引顺序=isnull(h.排序,'')
FROM syscolumns a
left join systypes b on a.xtype=b.xusertype
inner join sysobjects d on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join syscomments e on a.cdefault=e.id
left join sysproperties g on a.id=g.id and a.colid=g.smallid
left join sysproperties f on d.id=f.id and f.smallid=0
left join(--这部分是索引信息,如果要显示索引与表及字段的对应关系,可以只要此部分
select 索引名称=a.name,c.id,d.colid
,排序=case indexkey_property(c.id,b.indid,b.keyno,'isdescending')
when 1 then '降序' when 0 then '升序' end
from sysindexes a
join sysindexkeys b on a.id=b.id and a.indid=b.indid
join (--这里的作用是有多个索引时,取索引号最小的那个
select id,colid,indid=min(indid) from sysindexkeys
group by id,colid) b1 on b.id=b1.id and b.colid=b1.colid and b.indid=b1.indid
join sysobjects c on b.id=c.id and c.xtype='U' and c.name<>'dtproperties'
join syscolumns d on b.id=d.id and b.colid=d.colid
where a.indid not in(0,255)
) h on a.id=h.id and a.colid=h.colid
where d.name='orders' --如果只查询指定表,加上此条件
order by a.id,a.colorder

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lotto 2005-02-19
这个我已经看过了,但不能满足我的要求啊,我的要求是要象Sql脚本那样形成索引、主键信息
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dorisnet 2005-02-18
参考

如何查看table的栏位信息
SELECT
表名=case when a.colorder=1 then d.name else '' end,
表说明=case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序号=a.colorder,
字段名=a.name,
标识=case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
主键=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid
))) then '√' else '' end,
类型=b.name,
占用字节数=a.length,
长度=COLUMNPROPERTY(a.id,a.name,'PRECISION'),
小数位数=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
允许空=case when a.isnullable=1 then '√'else '' end,
默认值=isnull(e.text,''),
字段说明=isnull(g.[value],'')
FROM syscolumns a
left join systypes b on a.xusertype=b.xusertype
inner join sysobjects d on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join syscomments e on a.cdefault=e.id
left join sysproperties g on a.id=g.id and a.colid=g.smallid
left join sysproperties f on d.id=f.id and f.smallid=0
--where d.name='table_name' --如果要查询特定table,加上这句
order by a.id,a.colorder
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xuam 2005-02-18
select * from sysindexes
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