hibernate的问题，请指点一二！

zeq258 2005-03-25 01:29:40

我的程序：
POJO
PersonMedel.java
-------------------------------------------------------------
package hibernate01;
import java.io.Serializable;

public class PersonModel implements Serializable {
private String name;
private String password;

public void setName(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setPassword(String pasasword) {
this.password=password;
}
public String getPassword() {
return password;
}
}

PersonModel.hbm.xml
-----------------------------------------------------------------
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 2.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-2.0.dtd" >
<hibernate-mapping>

<class
name="hibernate01.PersonModel"
table="yonghu"
>
<id
name="name"
type="java.lang.String"
column="name"
>
<generator class="assigned" />
</id>
<property
name="password"
type="java.lang.String"
column="password"
length="255"
/>

</class>
</hibernate-mapping>

只有两个属性！

对数据库的操作 Client.java
---------------------------------------------------------------
package hibernate01;

import net.sf.hibernate.Session;
import net.sf.hibernate.Transaction;
import net.sf.hibernate.SessionFactory;
import net.sf.hibernate.cfg.Configuration;
import net.sf.hibernate.tool.hbm2ddl.SchemaExport;
import net.sf.hibernate.cache.HashtableCacheProvider;
public class Client
{
private static SessionFactory sessionFactory;
public static String asc(String str){
try{
byte b[] = str.getBytes("ISO-8859-1");
str = new String(b);
return str;
}
catch(Exception e){ return null;}
}
public static void main(String[] args) throws Exception
{
Configuration conf = new Configuration().addClass(PersonModel.class);
sessionFactory = conf.buildSessionFactory();
Session s = sessionFactory.openSession();
Transaction t = s.beginTransaction();

PersonModel yuj = new PersonModel();
yuj.setName(asc("11"));
yuj.setPassword("11");
PersonModel yuj1 = new PersonModel();
yuj1.setName("22");
yuj1.setPassword("22");

//持久化
s.save(yuj); //此时yuj已经可以在数据库中找到
s.save(yuj1);
//s.flush();
t.commit();
s.close();
}
}

我的问题，在对数据库的插入操作，为什么只插入了name字段，password字段为 null

请问原因？

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