如何区分WM_LBUTTONDOWN和WM_LBUTTONDBLCLK消息？

[WiseNeuro]

我想实现如下效果：
当在窗体的任务栏上双击鼠标左键时显示窗体，当单击鼠标左键时显示一个菜单。像qq那样的效果。消息处理程序如下：
void __fastcall TFormMain::MyNotify(TMessage& Msg)
{
POINT MousePos;

switch(Msg.LParam)
{
case WM_RBUTTONUP:
if (GetCursorPos(&MousePos))
{
PopupMenuSystem->PopupComponent = FormMain;
SetForegroundWindow(Handle);
PopupMenuSystem->Popup(MousePos.x, MousePos.y);
}
else
Show();
break;
case WM_LBUTTONDBLCLK:
Show() ;
break;
case WM_LBUTTONDOWN:
if (GetCursorPos(&MousePos))
{
PopupMenuState->PopupComponent = FormMain;
SetForegroundWindow(Handle);
PopupMenuState->Popup(MousePos.x, MousePos.y);
}
else
Show() ;
break ;

default:
break;
}
TForm::Dispatch(&Msg);


但是，双击鼠标左键时，他也会发送单击消息，弹出菜单。我该怎样区分这两个消息，或如何实现我想要的效果。谢谢。

[tghost333]

用两个函数分别控制WM_NCLBUTTONDBLCLK和WM_NCLBUTTONLCLK
类似:
void __fastcall Change(TMessage &Message);
BEGIN_MESSAGE_MAP
MESSAGE_HANDLER(WM_NCLBUTTONDBLCLK, TMessage, Change);
END_MESSAGE_MAP(TForm);

[zhenyu362]

哈哈，我觉得只能用计时来做，因为WM_LBUTTONDBLCLK必定是跟在一个WM_LBUTTONDOWN后面，所以我想到的办法是这样：
static bool bDBLCLK=false;
case WM_LBUTTONDBLCLK:
bDBLCLK=true;
Show() ;
break;
case WM_LBUTTONDOWN:
Timer1->Enable=true;

................
TimerProc
{
if(bDBCLK)
{bDBCLK=false;}
else
{ your code here....}
}

把Timer的intervalue设置成1s就够了

[WiseNeuro]

ok
搞定