请教 : fatal error C1001: INTERNAL COMPILER ERROR

lingzantia 2005-05-11 10:53:42
我用VC6.0编译文件,提示fatal error C1001: INTERNAL COMPILER ERROR错误,该怎么解决?
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lingzantia 2005-05-11
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下面是我的代码,分为3个.cpp和2个.h文件:

//main.cpp
#include <iostream>
using namespace std;

#include "test.h"
#include "three_d.h"

void main(void)
{
test menu;
}



//three_d.h
#ifndef THREE_D_H
#define THREE_D_H

class three_d
{
private:
int x, y, z;
void init();
public:
three_d();
three_d(int a,int b,int c);
~three_d();
friend three_d operator+(const three_d &obj_1, const three_d &obj_2);
friend three_d operator--(three_d &obj, int);
friend ostream &operator<<(ostream &out, const three_d &obj);
friend istream &operator>>(istream &in, three_d &obj);.
three_d operator++();
three_d operator-=(const three_d &obj);
};

#endif


//three_d.cpp
#include <iostream>
using namespace std;
#include "three_d.h"

void three_d::init()
{
cout << "Input the three_d : ";
cin >> x >> y >> z;
}

three_d::three_d()
{
init();
}

three_d::three_d(int a,int b,int c) : x(a), y(b), z(c)
{}

three_d::~three_d(){}

three_d three_d::operator ++()
{
++x;
++y;
++z;
return *this;
}

three_d three_d::operator -=(const three_d &obj)
{
x -= obj.x;
y -= obj.y;
z -= obj.z;
return *this;
}

three_d operator+(const three_d &obj_1, const three_d &obj_2)
{
return three_d(obj_1.x + obj_2.x, obj_1.y + obj_2.y, obj_1.z + obj_2.z);
}

three_d operator--(three_d &obj, int)
{
x--;
y--;
z--;
return *this;
}

ostream &operator<<(ostream &out, const three_d &obj)
{
out << "The three_d is : ";
out << odj.x;
out << ", ";
out << obj.y;
out << ", ";
out << obj.z;
out << endl;

return out;
}

istream &operator>>(istream &in, three_d &obj)
{
in >> obj.x;
in >> obj.y;
in >> obj.z;

return in;
}


//test.h
#ifndef TEST_H
#define TEST_H

class test
{
public:
test();
~test();
void menu();
};

#endif


//test.cpp
#include <iostream>
using namespace std;
#include "test.h"
#include "three_d.h"

test::test(){}

test::~test(){}

void test::menu()
{
char ch;

cout << "选项\n";
cout << "================================================\n";
cout << "1、两对象求和 2、对象对自身求差\n";
cout << "3、前自增 4、后自减\n";
cout << "5、退出\n";
cout << "================================================\n\n";

cout << "选择 : ";
cin >> ch;

do
{
switch(ch)
{
case '1' : three_d obj_1, obj_2;
cout << obj_1 + obj_2 << endl;
break;
case '2' : three_d obj_1, obj_2;
cout << obj_1 -= obj_2 << endl;
break;
case '3' : three_d obj;
cout << ++obj << endl;
break;
case '4' : three_d obj;
cout << obj-- << endl;
break;
case '5' : return;
default : cout << "错误的选择!\n";
}

cout << "继续操作?[是(Y or y) / 不(any other key)]";
cin >> ch;
}while ( (ch == 'Y') || (ch == 'y') );
}
lingzantia 2005-05-11
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大家帮帮忙!
lingzantia 2005-05-11
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晕,我也用MSDN,可是英文太菜了,麻烦翻译一下,好不?
277894613 2005-05-11
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Fatal Error C1001
INTERNAL COMPILER ERROR
(compiler file 'file', line number)

This error is most often generated in one of two cases:

Failure to recover the compiler's internal state following detection of a syntax error in the program. The first pass of the compiler will occasionally fail when attempting to recover its state following the detection of a malformed program. Typically, the compiler will have printed an error message (or messages) and will later produce an internal compiler error. In most cases, fixing the errors reported in your code and recompiling will solve the problem.


Failure of the code generator to find a way to generate correct code for a construct. This is most often caused by the interaction of an expression and an optimization option. The optimization has generated a tree which the compiler does not know how to handle. Such a problem can often be fixed by removing one or more optimization options when compiling the particular function containing the line indicated in the error message.
If no error messages have been emitted prior to the internal compiler error, then the next step is to determine which pass of the compiler is emitting the internal compiler error. This can be determined by recompiling the application with the /Bd option included. The /Bd option will cause each pass to print its name and arguments when it is invoked. The last pass invoked before the error is emitted is the one responsible.

If the pass indicated is P1, then the likely problem is still error recovery, as in number one above, but it is happening before the compiler has had a chance to emit the error message for the error it has just discovered. In such a case, examine the line on which the internal compiler error is reported. This line may also contain an unreported syntax error. Fixing any errors you find on that line will solve the internal compiler error in most cases. If you cannot find any error on that line or on the line previous to the one reported, contact Microsoft Product Support Services for help.

If the pass indicated is P2, then the problem can usually be fixed by removing one or more optimization options (or using a different code generator). You can determine which option is at fault by removing them one at a time and recompiling until the message goes away. Generally the last one removed is the problem and all other optimizations can be used safely. The most common culprits are /Og, /Oi, and /Oa. Once the offending optimization is discovered, it need not be turned off for the entire compilation. The offending optimization can be disabled with the optimize pragma while compiling the function where the error occurred, but enabled for the rest of the module.

More rarely, such errors occur at very low optimization levels or even when optimization is disabled. In such cases, rewriting the line where the error is reported (or possibly several lines including the one causing the error) may be a solution. If none of these options works, consult the technical support help file or the technical support section in one of your manuals.
=====================================================================================
我遇到过,一直没有解决,竟然放弃了,遗憾
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