(30x+11)(30y+19) ,x=0 to 50 ,y=0 to 50 ,if Mod[(30x+11)(30y+19),210]=89 and Mod[(30x+11)(30y+19),2310]=1139 and Mod[(30x+11)(30y+19),210]=1139 ,输出 x和y,
望高手帮忙编一个,示范一下,谢谢.
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如何用Delphi编程进行计算
我是新手,想用Delphi编程进行计算,不知道怎样编写,比如 (30x+11)(30y+19) ,x=0 to 50 ,y=0 to 50 ,if Mod[(30x+11)(30y+19),210]=89 and Mod[(30x+11)(30y+19),2310]=1139 and Mod[(30x+11)(30y+19),210]=1139 ,输出 x和y, 望高手帮忙编一个,示范一下,谢谢.
uses
SysUtils;
var
i, x, y: Intger
begin
for x:= 0 to 50 do begin
for y:= 0 to 50 do begin
i:= (30 * x + 11) * (30 * y + 19);
if (i mod 210 = 89)
and (i mod 2310 = 1139)
and (i mod 210 = 1139) then begin // 1139 > 210 ???????????
// OUTPUT.........
end;
end;
end;
for x:= 0 to 50 do begin
for y:= 0 to 50 do begin
i:= (30 * x + 11) * (30 * y + 19);
if (i mod 210 = 89)
and (i mod 2310 = 1139)
and (i mod 210 = 1139) then begin // 1139 > 210 ???????????
// OUTPUT.........
end;
end;
end;