compile table limit exceeded,可能是什么问题? [问题点数:80分,结帖人CSDN]

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time limit exceeded!!为什么???
[code=C/C++]rn#includernint main()rn int i,n,a[2];rn for(i=0;i,a[i]);rn rn return 0;rnrn[/code]rn怎么会time <em>limit</em> <em>exceeded</em>呢??
1482 Memory Limit Exceeded
http://acm.zju.edu.cn/show_problem.php?pid=1482rnrn#include rnchar maze[3001][3001];rn rnvoid f(int s,int h)rnrn if(maze[s][h]==0)rn rn maze[s][h]=1;rn f(s,h+1);rn f(s-1,h);rn f(s,h-1);rn f(s+1,h);rn rnrnrnrnrnint main()rnrn int size,s,h;rn int staus,count=0;rn cin>>size;rn for(h=0;h>staus;rn maze[s][h]=staus;rn rn for(s=1;s<
Time limit exceeded怎么回事啊?
题目是这样的:rnInputrnInput contains an integer N in the first line, and then N lines follow. rnEach line starts with a integer M, and then M integers follow in the same line. rnrnOutputrnFor each group of input integers you should output their sum in one line, rnand with one line of output for each line in input. rnrnSample Inputrn2rn4 1 2 3 4rn5 1 2 3 4 5rnrnSample Outputrn10rn15rnrn我编的代码是这样的:rn#include rnrnint main()rnrn rn int k, n, i, sum, num[100];rn scanf("%d", &k);rn while (k--)rn rn while (scanf("%d", &n) && (n!=0)) rn rn for (i=0; i
java.lang.OutOfMemoryError: GC overhead limit exceeded
在电脑上调试的时候是可以的,放在服务器上就不行了,服务器是window7,tomcat55版本,抱着个错误,代码是大概1000条数据和数据库中20w数据做比较的时候,第一次可以,第二次就不行了,重启tomcat就可以了,这是什么原因,为什么开发的时候是好好的,导入多次都没问题![img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/003/monkey/35.gif][/img]
leetcode 提示Time Limit Exceeded
rt, 题目如下rnYou are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.rnrnInput: (2 -> 4 -> 3) + (5 -> 6 -> 4)rnOutput: 7 -> 0 -> 8rnrn我的代码是rn[code=c] rnclass Solution rnrnpublic:rnrn ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) rn rnrn if (l1 == NULL) return l2; rn if (l2 == NULL) return l1;rn ListNode* p = l1;rn ListNode* q = l2;rn ListNode* r = NULL; //指向当前结点的前趋rn int Psum = 0;rn while ( p && q )rn rn rn int sum = p->val + q->val + Psum;rn int Nsum = sum%10; //rn p->val= Nsum;rn Psum = sum/10; // 和 是否大于10rn r=p; rn p=p->next;rn q=q->next;rn rn rn while (q)rn rn rn int tmp = (q->val + Psum)%10;rn Psum = tmp/10;rn r->next = new ListNode (tmp);rn r=r->next;rn rn rn while (p)rn rn rn p->val = (p->val + Psum)%10;rn Psum = p->val/10; rn rn rn if ( Psum ) rn ListNode* v= new ListNode (Psum);rn r->next = v;rn r=v;rn rn return l1;rn rn;[/code]rnrn我的思路是先处理两个链表长度相同的部分, 然后把相加得到的和直接赋值给第一个链表, 对于超出部分, 则新建结点, 然后接到第一个链表上. 请问哪里错了..
怎么解决Output Limit Exceeded
提交时会出现Output Limit Exceeded要怎么解决呢?就下面这个代码rnrn#include "stdafx.h"rn#includernusing namespace std;rnrnint main()rnrn char a,b,c,t;rn while(1)rn rn cin>>a>>b>>c;rn if(a>b)rn rn t=a;a=b;b=t;rn rn if(a>c)rn rn t=a;a=c;c=t;rn rn if(b>c)rn rn t=b;b=c;c=t;rn rn cout<
Leetcode提交代码Time Limit Exceeded
在Leetcode上面提交代码(第三题:Longest Substring Without Repeating Characters),提示Time Limit Exceeded。我在VS上面可以正常运行,对于Leetcode的测试例子,运行时间大约是100ms。rnrn我的代码如下:rn//暴力搜寻,从头到尾遍历子串rnclass Solution rnpublic:rn/ int lengthOfLongestSubstring(string s) rn int max = 0;rn string str;rn for (int index_x = s.size(); index_x >= 0; --index_x)rn rn for (int index_y = 0; index_y < index_x; ++index_y)rn rn str=s.substr(index_y, index_x-index_y);rn if (str.size() max)rn rn max = str.size();rn break;rn rn rn rn rn return max; rn rn;rnrn//自己实现查询重复函数,但效率没有上面的高rnclass Solution rnpublic:rn int lengthOfLongestSubstring(string s) rn int max = 0;rn string str;rn for (int index_x = s.size(); index_x >= 0; --index_x)rn rn for (int index_y = 0; index_y < index_x; ++index_y)rn rn str=s.substr(index_y, index_x-index_y);rn if (str.size() max)rn rn max = str.size();rn break;rn rn rn rn rn return max; rn rnrn bool unique_str(string str_u)rn rn bool flag;rn rn set set_str;rn for (int i = 0; i < str_u.size(); ++i)rn rnrn if (set_str.count(str_u.at(i)))rn rn flag = false;rn break;rn rn elsern rn flag = true;rn rn set_str.insert(str_u.at(i));rn rn return flag;rn rn;
在线测试:Time Limit Exceeded
北大的在线测试rn题目在:http://poj.org/problem?id=1061rn我用java写的,给的结果就是:Time Limit Exceeded,我知道java的运行速度比较慢,谁能帮我有话一下,可以在那个系统中通过,分就全部是谁的了?rn贴上我的代码:rn[code=Java]rnimport java.util.*;rnpublic class Main rn public static void main(String[] args) throws Exceptionrn int x=0,y=0,m=0,n=0,l=0,count = 0;rn Scanner cin = new Scanner(System.in);rn x = cin.nextInt();rn y = cin.nextInt();rn m = cin.nextInt();rn n = cin.nextInt();rn l = cin.nextInt();rn rn if(m==n)rn System.out.println("Impossible");rn return;rn rn while (x!=y) rn count++;rn x+=m;rn y+=n;rn if (x>l-1) rn x=x%l;rn rn if (y>l-1) rn y=y%l;rn rn rn System.out.println(count);rn rnrn[/code]
compiler table limit exceeded"??">BC 编译DOS程序, 出错"compiler table limit exceeded"??
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Problem DescriptionrnYour task is to calculate the sum of some integers.rnrnInputrnInput contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. rnrnOutputrnFor each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.rnrnSample Inputrn3rn4 1 2 3 4rn5 1 2 3 4 5rn3 1 2 3rnrnSample Outputrn10rnrn15rnrn6rn#include rn#include rnrnint main()rnrn int n,m1,m2,m3;rn int sum1=0,sum2=0,sum3=0;rn int temp;rn scanf("%d",&n);rn while(--n)rn rn scanf("%d",&m1);rn while(m1--)rn rn scanf("%d",&temp);rn sum1 += temp;rn rn scanf("%d",&m2);rn while(m2--)rn rn scanf("%d",&temp);rn sum2 += temp;rn rn scanf("%d",&m3);rn while(m3--)rn rn scanf("%d",&temp);rn sum3+=temp;rn rn printf("%d\n\n%d\n\n%d\n\n",sum1,sum2,sum3);rn rn return 0;rn rn
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杭电1062rnSample Inputrn3rnolleh !dlrowrnm'I morf .udhrnI ekil .mcarn rnrnSample Outputrnhello world!rnI'm from hdu.rnI like acm.rn代码如下:rn#includern#includernusing namespace std;rnint main()rnrn int head,blank_space;rn scanf_s("%d",&head);rn blank_space=getchar();rn while (head--)rn rn char p[100];rn gets_s(p);rn int len=strlen(p);rn int j;rn int record=0;rn for (int i=0;i
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1.服务器相关配置问题通过修改开发坏境IDE运行参数或者线上环境启动修改配置-Xmx768m来扩大允许占用内存大小2.程序存在相应对象无法被GC垃圾回收处理程序部分代码BUG导致内存溢出,GC无法做出处理,我们需要借助工具来分析在哪里出现这样的问题。JDK的jhat命令能帮助我们。查看jhat展示的网页信息中,一般查看堆异常情况主要看这个两个部分: Show instance counts for...
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当scanf读取成功时返回读取到的参数数量,否则返回EOF。EOF是一个宏,定义在stdio.h里,值为-1。以下面代码为例,正确的判断方式有:scanf(&quot;%d-%d-%d&quot;, &amp;amp;year, &amp;amp;month, &amp;amp;day) != EOFscanf(&quot;%d-%d-%d&quot;, &amp;amp;year, &amp;amp;month, &amp;amp;day) == 3或~scanf(&quot;%d-%d-%...
关于C语言OJ的一道题:Time Limit Exceeded
hihoCoder上的一道关于KMP算法的一道题,题目描述如下:n#1015 : KMP算法n时间限制:1000msn单点时限:1000msn内存限制:256MBn描述n小Hi和小Ho是一对好朋友,出生在信息化社会的他们对编程产生了莫大的兴趣,他们约定好互相帮助,在编程的学习道路上一同前进。nn这一天,他们遇到了一只河蟹,于是河蟹就向小Hi和小Ho提出了那个经典的问题:“小Hi和小Ho,你们能不能够判断一段文字(原串)里面是不是存在那么一些……特殊……的文字(模式串)?”nn小Hi和小Ho仔细思考了一下,觉得只能想到很简单的做法,但是又觉得既然河蟹先生这么说了,就肯定不会这么容易的让他们回答了,于是他们只能说道:“抱歉,河蟹先生,我们只能想到时间复杂度为(文本长度 * 特殊文字总长度)的方法,即对于每个模式串分开判断,然后依次枚举起始位置并检查是否能够匹配,但是这不是您想要的方法是吧?”nn河蟹点了点头,说道:”看来你们的水平还有待提高,这样吧,如果我说只有一个特殊文字,你能不能做到呢?“nn小Ho这时候还有点晕晕乎乎的,但是小Hi很快开口道:”我知道!这就是一个很经典的模式匹配问题!可以使用KMP算法进行求解!“nn河蟹满意的点了点头,对小Hi说道:”既然你知道就好办了,你去把小Ho教会,下周我有重要的任务交给你们!“nn”保证完成任务!”小Hi点头道。nn提示一:KMP的思路nn提示二:NEXT数组的使用nn提示三:如何求解NEXT数组nn输入n第一行一个整数N,表示测试数据组数。nn接下来的N*2行,每两行表示一个测试数据。在每一个测试数据中,第一行为模式串,由不超过10^4个大写字母组成,第二行为原串,由不超过10^6个大写字母组成。nn其中N)n n sum++;n ori=ori-1-*(next+i-1);n pat=p;n i=0;n n n n return sum;nnn但每次提交结果都是:nTime Limit Exceeded TLE 用户程序运行时间超过题目的限制n怎么优化一下我的代码才能是它AC啊?!求大神指导啊。
linux 下 报java.lang.OutOfMemoryError: GC overhead limit exceeded错误
操作系统是linux,服务器是tomcatrnrn每次运行java web的时候,报“java.lang.OutOfMemoryError: GC overhead <em>limit</em> <em>exceeded</em>”rnrn我从网上查了下,其答案:rnrn[color=#FF0000]rn一、异常如下:Exception in thread "main" java.lang.OutOfMemoryError: GC overhead <em>limit</em> <em>exceeded</em> 二、解释:JDK6新增错误类型。当GC为释放很小空间占用大量时间时抛出。一般是因为堆太小。导致异常的原因:没有足够的内存。 三、解决方案: 1、查看系统是否有使用大内存的代码或死循环。2、可以添加JVM的启动参数来限制使用内存:-XX:-UseGCOverheadLimitrn [/color]rn我想问下:rn2、可以添加JVM的启动参数来限制使用内存:-XX:-UseGCOverheadLimitrn在linux 下,该修改tomcat哪个文件,该把这段话加在什么地方哦?谢谢rnrn
mapreduce 错误:failed Map Tasks exceeded allowed limit
程序在处理20M一下的文件时没有问题,超过20以后执行一直失败,报错信息:如提示rnjava.lang.RuntimeException: PipeMapRed.waitOutputThreads(): subprocess failed with code 1rnat org.apache.hadoop.streaming.PipeMapRed.waitOutputThreads(PipeMapRed.java:362)rnat org.apache.hadoop.streaming.PipeMapRed.mapRedFinished(PipeMapRed.java:576)rnat org.apache.hadoop.streaming.PipeMapper.close(PipeMapper.java:135)rnat org.apache.hadoop.mapred.MapRunner.run(MapRunner.java:57)rnat org.apache.hadoop.streaming.PipeMapRunner.run(PipeMapRunner.java:36)rnat org.apache.hadoop.mapred.MapTask.runOldMapper(MapTask.java:436)rnat org.apache.hadoop.mapred.MapTask.run(MapTask.java:372)rnat org.apache.hadoop.mapred.Child$4.run(Child.java:255)rnat java.security.AccessController.doPrivileged(Native Method)rnat javax.security.auth.Subject.doAs(Subject.java:396)rnat org.apache.hadoop.security.UserGroupInformation.doAs(UserGroupInformation.java:1149)rnat org.apache.hadoop.mapred.Child.main(Child.java:249)rnrn执行过程打印信息:rnpackageJobJar: [/tmp/RtmpbrxmDJ/rmr-local-env5b7e66089a6f, /tmp/RtmpbrxmDJ/rmr-global-env5b7e6fc159e8, /tmp/RtmpbrxmDJ/rmr-streaming-map5b7e11d32952, /tmp/RtmpbrxmDJ/rmr-streaming-reduce5b7e40455eb9, /home/hadoop/tmp/hadoop-unjar4800417805397835354/] [] /tmp/streamjob7747076070321950699.jar tmpDir=nullrn14/01/02 03:36:20 INFO mapred.FileInputFormat: Total input paths to process : 1rn14/01/02 03:36:20 INFO streaming.StreamJob: getLocalDirs(): [/home/hadoop/mapreduce/local]rn14/01/02 03:36:20 INFO streaming.StreamJob: Running job: job_201401020330_0003rn14/01/02 03:36:20 INFO streaming.StreamJob: To kill this job, run:rn14/01/02 03:36:20 INFO streaming.StreamJob: /root/hadoop-1.1.2/libexec/../bin/hadoop job -Dmapred.job.tracker=192.168.2.6:9001 -kill job_201401020330_0003rn14/01/02 03:36:20 INFO streaming.StreamJob: Tracking URL: http://192.168.2.6:50030/jobdetails.jsp?jobid=job_201401020330_0003rn14/01/02 03:36:22 INFO streaming.StreamJob: map 0% reduce 0%rn14/01/02 03:36:37 INFO streaming.StreamJob: map 2% reduce 0%rn14/01/02 03:36:42 INFO streaming.StreamJob: map 3% reduce 0%rn14/01/02 03:36:45 INFO streaming.StreamJob: map 6% reduce 0%rn14/01/02 03:36:48 INFO streaming.StreamJob: map 8% reduce 0%rn14/01/02 03:36:51 INFO streaming.StreamJob: map 12% reduce 0%rn14/01/02 03:36:54 INFO streaming.StreamJob: map 14% reduce 0%rn14/01/02 03:36:58 INFO streaming.StreamJob: map 18% reduce 0%rn14/01/02 03:37:01 INFO streaming.StreamJob: map 21% reduce 0%rn14/01/02 03:37:04 INFO streaming.StreamJob: map 22% reduce 0%rn14/01/02 03:37:07 INFO streaming.StreamJob: map 25% reduce 0%rn14/01/02 03:37:10 INFO streaming.StreamJob: map 28% reduce 0%rn14/01/02 03:37:13 INFO streaming.StreamJob: map 31% reduce 0%rn14/01/02 03:37:30 INFO streaming.StreamJob: map 35% reduce 0%rn14/01/02 03:37:31 INFO streaming.StreamJob: map 44% reduce 0%rn14/01/02 03:37:34 INFO streaming.StreamJob: map 46% reduce 0%rn14/01/02 03:37:35 INFO streaming.StreamJob: map 47% reduce 0%rn14/01/02 03:37:37 INFO streaming.StreamJob: map 49% reduce 0%rn14/01/02 03:37:40 INFO streaming.StreamJob: map 50% reduce 0%rn14/01/02 03:37:41 INFO streaming.StreamJob: map 52% reduce 0%rn14/01/02 03:37:43 INFO streaming.StreamJob: map 55% reduce 0%rn14/01/02 03:37:46 INFO streaming.StreamJob: map 58% reduce 0%rn14/01/02 03:37:50 INFO streaming.StreamJob: map 60% reduce 0%rn14/01/02 03:37:55 INFO streaming.StreamJob: map 62% reduce 0%rn14/01/02 03:37:56 INFO streaming.StreamJob: map 64% reduce 0%rn14/01/02 03:37:58 INFO streaming.StreamJob: map 65% reduce 0%rn14/01/02 03:38:04 INFO streaming.StreamJob: map 67% reduce 0%rn14/01/02 03:38:06 INFO streaming.StreamJob: map 71% reduce 0%rn14/01/02 03:38:09 INFO streaming.StreamJob: map 74% reduce 0%rn14/01/02 03:38:12 INFO streaming.StreamJob: map 76% reduce 0%rn14/01/02 03:38:15 INFO streaming.StreamJob: map 80% reduce 0%rn14/01/02 03:38:18 INFO streaming.StreamJob: map 83% reduce 0%rn14/01/02 03:38:22 INFO streaming.StreamJob: map 85% reduce 0%rn14/01/02 03:38:25 INFO streaming.StreamJob: map 87% reduce 0%rn14/01/02 03:38:28 INFO streaming.StreamJob: map 91% reduce 0%rn14/01/02 03:38:31 INFO streaming.StreamJob: map 93% reduce 0%rn14/01/02 03:38:35 INFO streaming.StreamJob: map 95% reduce 0%rn14/01/02 03:38:39 INFO streaming.StreamJob: map 98% reduce 0%rn14/01/02 03:38:42 INFO streaming.StreamJob: map 100% reduce 0%rn14/01/02 03:39:13 INFO streaming.StreamJob: map 50% reduce 0%rn14/01/02 03:39:27 INFO streaming.StreamJob: map 51% reduce 0%rn14/01/02 03:39:30 INFO streaming.StreamJob: map 52% reduce 0%rn14/01/02 03:39:34 INFO streaming.StreamJob: map 53% reduce 0%rn14/01/02 03:39:48 INFO streaming.StreamJob: map 53% reduce 17%rn14/01/02 03:39:50 INFO streaming.StreamJob: map 56% reduce 17%rn14/01/02 03:39:53 INFO streaming.StreamJob: map 59% reduce 17%rn14/01/02 03:39:56 INFO streaming.StreamJob: map 63% reduce 17%rn14/01/02 03:39:59 INFO streaming.StreamJob: map 65% reduce 17%rn14/01/02 03:40:02 INFO streaming.StreamJob: map 67% reduce 17%rn14/01/02 03:40:04 INFO streaming.StreamJob: map 69% reduce 17%rn14/01/02 03:40:07 INFO streaming.StreamJob: map 73% reduce 17%rn14/01/02 03:40:10 INFO streaming.StreamJob: map 75% reduce 17%rn14/01/02 03:40:14 INFO streaming.StreamJob: map 78% reduce 17%rn14/01/02 03:40:17 INFO streaming.StreamJob: map 80% reduce 17%rn14/01/02 03:40:20 INFO streaming.StreamJob: map 83% reduce 17%rn14/01/02 03:40:24 INFO streaming.StreamJob: map 86% reduce 17%rn14/01/02 03:40:26 INFO streaming.StreamJob: map 88% reduce 17%rn14/01/02 03:40:29 INFO streaming.StreamJob: map 90% reduce 17%rn14/01/02 03:40:32 INFO streaming.StreamJob: map 94% reduce 17%rn14/01/02 03:40:36 INFO streaming.StreamJob: map 96% reduce 17%rn14/01/02 03:40:39 INFO streaming.StreamJob: map 98% reduce 17%rn14/01/02 03:40:42 INFO streaming.StreamJob: map 100% reduce 17%rn14/01/02 03:40:47 INFO streaming.StreamJob: map 50% reduce 17%rn14/01/02 03:41:02 INFO streaming.StreamJob: map 52% reduce 17%rn14/01/02 03:41:05 INFO streaming.StreamJob: map 55% reduce 17%rn14/01/02 03:41:08 INFO streaming.StreamJob: map 57% reduce 17%rn14/01/02 03:41:11 INFO streaming.StreamJob: map 60% reduce 17%rn14/01/02 03:41:14 INFO streaming.StreamJob: map 63% reduce 17%rn14/01/02 03:41:17 INFO streaming.StreamJob: map 66% reduce 17%rn14/01/02 03:41:20 INFO streaming.StreamJob: map 68% reduce 17%rn14/01/02 03:41:23 INFO streaming.StreamJob: map 70% reduce 17%rn14/01/02 03:41:26 INFO streaming.StreamJob: map 74% reduce 17%rn14/01/02 03:41:29 INFO streaming.StreamJob: map 75% reduce 17%rn14/01/02 03:41:32 INFO streaming.StreamJob: map 78% reduce 17%rn14/01/02 03:41:35 INFO streaming.StreamJob: map 81% reduce 17%rn14/01/02 03:41:39 INFO streaming.StreamJob: map 83% reduce 17%rn14/01/02 03:41:41 INFO streaming.StreamJob: map 86% reduce 17%rn14/01/02 03:41:44 INFO streaming.StreamJob: map 88% reduce 17%rn14/01/02 03:41:47 INFO streaming.StreamJob: map 91% reduce 17%rn14/01/02 03:41:50 INFO streaming.StreamJob: map 94% reduce 17%rn14/01/02 03:41:53 INFO streaming.StreamJob: map 96% reduce 17%rn14/01/02 03:41:56 INFO streaming.StreamJob: map 99% reduce 17%rn14/01/02 03:42:01 INFO streaming.StreamJob: map 50% reduce 17%rn14/01/02 03:42:10 INFO streaming.StreamJob: map 52% reduce 17%rn14/01/02 03:42:13 INFO streaming.StreamJob: map 56% reduce 17%rn14/01/02 03:42:16 INFO streaming.StreamJob: map 59% reduce 17%rn14/01/02 03:42:19 INFO streaming.StreamJob: map 61% reduce 17%rn14/01/02 03:42:22 INFO streaming.StreamJob: map 64% reduce 17%rn14/01/02 03:42:25 INFO streaming.StreamJob: map 66% reduce 17%rn14/01/02 03:42:28 INFO streaming.StreamJob: map 69% reduce 17%rn14/01/02 03:42:31 INFO streaming.StreamJob: map 72% reduce 17%rn14/01/02 03:42:34 INFO streaming.StreamJob: map 75% reduce 17%rn14/01/02 03:42:37 INFO streaming.StreamJob: map 77% reduce 17%rn14/01/02 03:42:40 INFO streaming.StreamJob: map 80% reduce 17%rn14/01/02 03:42:43 INFO streaming.StreamJob: map 83% reduce 17%rn14/01/02 03:42:46 INFO streaming.StreamJob: map 85% reduce 17%rn14/01/02 03:42:49 INFO streaming.StreamJob: map 88% reduce 17%rn14/01/02 03:42:52 INFO streaming.StreamJob: map 90% reduce 17%rn14/01/02 03:42:55 INFO streaming.StreamJob: map 94% reduce 17%rn14/01/02 03:42:59 INFO streaming.StreamJob: map 96% reduce 17%rn14/01/02 03:43:02 INFO streaming.StreamJob: map 98% reduce 17%rn14/01/02 03:43:07 INFO streaming.StreamJob: map 50% reduce 17%rn14/01/02 03:43:10 INFO streaming.StreamJob: map 100% reduce 100%rn14/01/02 03:43:10 INFO streaming.StreamJob: To kill this job, run:rn14/01/02 03:43:10 INFO streaming.StreamJob: /root/hadoop-1.1.2/libexec/../bin/hadoop job -Dmapred.job.tracker=192.168.2.6:9001 -kill job_201401020330_0003rn14/01/02 03:43:10 INFO streaming.StreamJob: Tracking URL: http://192.168.2.6:50030/jobdetails.jsp?jobid=job_201401020330_0003rn14/01/02 03:43:10 ERROR streaming.StreamJob: Job not successful. Error: # of failed Map Tasks <em>exceeded</em> allowed <em>limit</em>. FailedCount: 1. LastFailedTask: task_201401020330_0003_m_000000rn14/01/02 03:43:10 INFO streaming.StreamJob: killJob...rnStreaming Command Failed!rnError in mr(map = map, reduce = reduce, combine = combine, vectorized.reduce, : rn hadoop streaming failed with error code 1rnCalls: QRcount -> mapreduce -> mrrnExecution haltedrn[root@localhost shell]# rnrn恳求诸位不吝赐教啊~~~
丢失的数字。。。。怎么老是Time Limit Exceeded。。望解
Total Submission: 825 Submission Accepted: 114 rnrnrnrnDescriptionrnrn有N个数字是来自一个长度为N+1的连续整数序列,但是给你的并不是有序的,请你帮忙找出来是缺失的那个数字是在序列的两边还是中间rnrnInputrnrn有多组测试数据,每组测试数据包括2行,第一行包括一个整数N(0rnusing namespace std;rnint a[10000];rnint main()rnint n,max,min,j=1;rnwhile(cin>>n&&n!=0)rnmax=-234567890;rnmin=234567890;rn for(int i=1;i>a[i];rn if(a[i]>max)max=a[i];rn if(a[i]
超级郁闷,4个方法都“Memory limit exceeded
题目是这样的:rn输入一个字符串,如果这个字符串是由in,input,out,output,puton,one组成,就返回YES,否则返回NO。rn时间限制是1秒,内存限制16M。每个字符串长度不超过10^7个字符。rnrnrn方法一:rnrn[code=C#]using System;rnusing System.Text.RegularExpressions;rnrnclass Programrnrnstatic void Main(string[] args)rnrnint lenNum = int.Parse(Console.ReadLine());rnfor (int i = 0; i < lenNum; i++)rnrnif (Regex.IsMatch(Console.ReadLine(), "^(?:one|out(?:put)?|in(?:put)?|puton)+$")) Console.WriteLine("YES");rnelse Console.WriteLine("NO");rnrnrn[/code]rnrnrn方法二:rn[code=C#]using System;rnclass Programrnrnstatic void Main(string[] args)rnrnint lenNum = int.Parse(Console.ReadLine());rnfor (int i = 0; i < lenNum; i++)rnrnif (Console.ReadLine().Replace("one","").Replace("puton","").Replace("output","").Replace("input","").Replace("out","").Replace("in","")=="") Console.WriteLine("YES");rnelse Console.WriteLine("NO");rnrnrn[/code]rnrnrn方法三:rn[code=C#]using System;rnclass Programrnrnstatic void Main(string[] args)rnrnint lenNum = int.Parse(Console.ReadLine());rnfor (int i = 0; i < lenNum; i++)rnConsole.WriteLine(Judge(Console.ReadLine()));rnrnrnrnstatic string Judge(string input)rnrnint pos = 0;rnfor (int i = input.Length - 1; i >= 0; i--)rnrnpos++;rnif (pos == 1||pos==4) continue;rnelse if (pos == 2)rnrnif (input.Substring(i, pos) == "in") pos = 0;rnelse continue;rnrnelse if (pos == 3)rnrnif (input.Substring(i, pos) == "one" || input.Substring(i, pos) == "out") pos = 0;rnelse continue;rnrnelse if (pos == 5)rnrnif (input.Substring(i, pos) == "input" || input.Substring(i, pos) == "puton") pos = 0;rnelse continue;rnrnelsernrnif (input.Substring(i, pos) == "output") pos = 0;rnelse return "NO";rnrnrnif (pos==0) return "YES";rnelse return "NO";rnrn[/code]rnrn方法四:rn[code=C#]using System;rn class Programrn rn static void Main(string[] args)rn rn int lenNum = int.Parse(Console.ReadLine());rn for (int i = 0; i < lenNum; i++)rn Console.WriteLine(JudgeInput(Console.ReadLine()));rnrnrn static string JudgeInput(string input)rn rn int pos = 0;rn for (int i = input.Length - 1; i >= 0; i--)rn rn pos++;rn switch (input[i])rn rn case 'p':rn if (pos == 5)rn rn if (input.Substring(i, 5) == "puton") pos = 0;rn else pos = -1;rn rn break;rn case 'i': rn if (pos==2||pos==5)rn rn if(input.Substring(i, pos) == "in"||input.Substring(i, pos) == "input") pos = 0; rn else pos = -1;rn rn else pos=-1;break;rn case 'o':rn if (pos == 3)rn rn if (input.Substring(i, pos) == "one" || input.Substring(i, pos) == "out") pos = 0;rn else pos = -1;rn rn else if (pos == 6)rn rn if (input.Substring(i, 6) == "output") pos = 0;rn else pos = -1;rn rn break;rn case 'n':rn case 'e':rn case 't':rn case 'u': break;rn default: pos = -1; break;rn rn if (pos < 0 || pos > 7) return "NO";rn rn if (pos==0) return "YES";rn else return "NO";rn rn[/code]rn rn rn
急!!android编译遇到java.lang.OutOfMemoryError: GC overhead limit exceeded错误
在编译android2.3的工程时遇到错误rn[color=#FF0000]UNEXPECTED TOP-LEVEL ERROR:rnjava.lang.OutOfMemoryError: GC overhead <em>limit</em> <em>exceeded</em>rn at java.util.HashSet.(HashSet.java:125)rn at com.android.dx.dex.code.StdCatchBuilder.getCatchTypes(StdCatchBuilder.java:97)rn at com.android.dx.dex.code.DalvCode.getCatchTypes(DalvCode.java:166)rn at com.android.dx.dex.file.CodeItem.addContents(CodeItem.java:126)rn at com.android.dx.dex.file.MixedItemSection.prepare0(MixedItemSection.java:280)rn at com.android.dx.dex.file.Section.prepare(Section.java:214)rn at com.android.dx.dex.file.DexFile.toDex0(DexFile.java:486)rn at com.android.dx.dex.file.DexFile.toDex(DexFile.java:196)rn at com.android.dx.command.dexer.Main.writeDex(Main.java:427)rn at com.android.dx.command.dexer.Main.run(Main.java:180)rn at com.android.dx.command.dexer.Main.main(Main.java:157)rn at com.android.dx.command.Main.main(Main.java:89)rnmake: *** [out/target/common/obj/JAVA_LIBRARIES/framework_intermediates/noproguard.classes-with-local.dex] Error 3[/color]rn编译环境为ubuntu10.10rnrn在网上搜索了一下解决方法rn[color=#0000FF]二、解释:rnJDK6新增错误类型。当GC为释放很小空间占用大量时间时抛出。rn一般是因为堆太小。导致异常的原因:没有足够的内存。rnrn三、解决方案:rn1、查看系统是否有使用大内存的代码或死循环。rn2、可以添加JVM的启动参数来限制使用内存:-XX:-UseGCOverheadLimit[/color]rn但是不知道如何去添加JVM启动参数rn哪位大虾能指点一下,给一个详细的流程。rnrnPS:相同的代码,在另一台配置一样的机器上可以编译通过,见鬼了..rn在线等rnrn
ACM简单题目 Time Limit Exceeded 求解释
ACM简单题目 Time Limit Exceeded 求解释rn月老使命rnTime Limit: 1000 ms Case Time Limit: 1000 ms Memory Limit: 64 MBrnTotal Submission: 26 Submission Accepted: 3rnDescriptionrncxlove曾经客串过月老(呵呵~~~只不过是给数字配对)。rn两个整数拼接成一个新数字之后,如果是3的倍数,则我们定义为幸福配对。rn现在有n个数字,月老的任务就是将其配对。rn现在请你帮助月老计算出最多能够有多少个幸福配对。rn例如:123和456可以拼接成123456,也可以组成456123。rnrnInputrn一个整数 T,表示有 T 组测试数据。(1,&a[i]);rn for(i=1;i
ACM 的一道题提交总是Time Limit Exceeded,求救
我搞了一个下午,得出的结论是本人的确是菜鸟,请各位大虾帮下忙!!!rn题目:rnEscape rnTime Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other)rnTotal Submission(s) : 15 Accepted Submission(s) : 0rnFont: Times New Roman | Verdana | Georgia rnFont Size: ← →rnProblem Descriptionrn2012 If this is the end of the world how to do? I do not know how. But now scientists have found that some stars, who can live, but some people do not fit to live some of the planet. Now scientists want your help, is to determine what all of people can live in these planets.rnInputrnMore set of test data, the beginning of each data is n (1 <= 100000rnOutputrnDetermine whether all people can live up to these starsrnIf you can output YES, otherwise output NO.rnSample Inputrn1 1rn1rn1rn2 2rn1 0rn1 0rn1 1rnSample OutputrnYESrnNOrnrn我的代码是:rn#includernusing namespace std;rnlong N;rnint M; rnint success=0;//是否成功标志 rnint nm_array[100000][10]; rnlong m_array[10];rnvoid backtrack(long n) //递归调用 rnrn long i,j;rn if(n==N)//如果是到了安排最后一个人了 rn rn for(i=0;i
zoj_1649出现Memory Limit Exceeded,各位大牛帮帮忙啊
原题链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=649rnrnrn#include rn#include rn#include rnusing namespace std;rnstruct nodernrn int x;rn int y;rn int step;rn;rnchar g[201][201];rnint main()rnrn int m,n,i,j;rn node start,end,temp,t,tx;rn queue q,x;rn bool c;rn int s[4][2]=0,1, 0,-1, 1,0, -1,0; rn while(scanf("%d%d",&m,&n)!=EOF)rn rn c=false;rn for(i=0;i=n||t.y=m)rn continue;rn if(g[t.y][t.x]=='.')rn rn // g[t.y][t.x]=t.step+1+'0'; rn t.step=t.step+1; rn q.push(t);rn rn if(g[t.y][t.x]=='x')rn rn // g[t.y][t.x]=t.step+1+'0';rn t.step=t.step+2;rn x.push(t);rn rn if(g[t.y][t.x]=='a') rn rn c=true;rn break;rn rn rn rn if(c) break;rn rn if(c) printf("%d\n",temp.step+1);rn else printf("Poor ANGEL has to stay in the prison all his life.\n");rn rn return 0;rnrnrn应该怎么改才行呢?求解释……
gcc: Internal error: File size limit exceeded (program as)
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杭电2028 Output Limit Exceeded,求高手解答。
#include "stdio.h"rnint n;rnint Gcd(int x,int y)rnrn int t;rn if(x
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PAT1019 数字黑洞 提交时Time Limit Exceeded
//PAT1019V1rn#include rnrnint FeiDiZeng(int n)rn int a[4];rn a[0]=n%10; //gern a[1]=n/10%10; //shirn a[2]=n/100%10; //bairn a[3]=n/1000; //qianrn int tmp,i,j;rn for(i=0;i,FDZ,FDJ,FDZ-FDJ);rnrn rnrnrnrn```rn rn```
【转载】关于android编译出现“GC overhead limit exceeded”的解决办法。
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pku上3378--crazy thairs老说我Output Limit Exceeded ,帮帮忙
#include"stdio.h"rn#include"stdlib.h"rn#define M 50000rnint trace(long a[],int x[],int t,int n,long double &count)rnrn int i,j,flag=0,z=0,tf=0,c=0,s=0,tmp[5]=0;rn if(t>n) rn rn //printf("%d ",x[0]);rn if(x[0])rn rn tmp[c++]=a[0];//printf("tmp:%d ",tmp[0]);rn rn for(i=1;itmp[c-1]&&a[i]=0;j--)rn if(x[j]==0) z++;rn rn if(n-z=0;j--) rn rn if(x[j]) rn rn flag=1;rn if(a[t]>a[j])//printf("* ");rn trace(a,x,t+1,n,count);rn break;rn rn //forrn if(!flag) trace(a,x,t+1,n,count);rn rn else if(!x[t]||t==0) rn //printf("** ");rn trace(a,x,t+1,n,count);rn rn return 0;rn rnint main()rnrn int c,n;rn scanf("%d",&n);rn while(n)rn rn long double count=0;rn if(n,count);continue;rn long a[M]=0;rn int i,j,x[M+1]=0,temp=0;rn //g[M]=0;rn for(i=0;i
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[img=https://img-bbs.csdn.net/upload/201809/05/1536110393_136531.png][/img] include include using namespace std; class complex { public: complex(){} complex(double m,double n) { this-&amp;amp;gt...
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请问可以怎样修改,以至于不会Time Limit Exceeded!!!!
数组去重排序rn#includernusing namespace std;rnvoid sort(int a[10001],int p)rn int same;rn for(int i=0;ia[j+1]) rn same=a[j+1];rn a[j+1]=a[j];rn a[j]=same;rn rn rn for(int i=0;i>n;rn int flag=1;rn for(int i=0;i>m;rn for(int j=0;j
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Out of range: size 3 exceeded max size limit 3
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如题!
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$limit
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Unable to compile class for JSP是个什么问题啊?
rnrnrn rn rn rn计数器演示程序rnrnrnrnrnrnrnrn您是第位访问者rnrnrnrn我把counter.java编译后,放在web-inf/classes目录下面,怎么运行的时候出来这个问题,偶才认识Jsp,请赐教。rntype Exception reportrnrnmessage rnrndescription The server encountered an internal error () that prevented it from fulfilling this request.rnrnexception rnrnorg.apache.jasper.JasperException: Unable to <em>compile</em> class for JSPrnrnAn error occurred at line: 12 in the jsp file: /test.jsprnrnGenerated servlet error:rn [javac] Compiling 1 source filernrnD:\Program Files\Apache Software Foundation\Tomcat 5.0\work\Catalina\localhost\web\org\apache\jsp\test_jsp.java:51: cannot resolve symbolrnsymbol : class counter rnlocation: class org.apache.jsp.test_jsprn counter counter = null;rn ^rnrnrnrnAn error occurred at line: 12 in the jsp file: /test.jsprnrnGenerated servlet error:rnD:\Program Files\Apache Software Foundation\Tomcat 5.0\work\Catalina\localhost\web\org\apache\jsp\test_jsp.java:53: cannot resolve symbolrnsymbol : class counter rnlocation: class org.apache.jsp.test_jsprn counter = (counter) pageContext.getAttribute("counter", PageContext.REQUEST_SCOPE);rn ^rnrnrnrnAn error occurred at line: 12 in the jsp file: /test.jsprnrnGenerated servlet error:rnD:\Program Files\Apache Software Foundation\Tomcat 5.0\work\Catalina\localhost\web\org\apache\jsp\test_jsp.java:55: cannot resolve symbolrnsymbol : class counter rnlocation: class org.apache.jsp.test_jsprn counter = new counter();rn ^rn3 errors
编译器compile
一个编译器原码,能编译原文件,文档了有详细说明-The original code a <em>compile</em>r can <em>compile</em> the original document, the document has a detailed description
Compile error?
#include rn#include rn#include rn#include rn#include rn#include rnrnstatic FILE *output_stream = (FILE *)0;rnrnchar *menu[] = rn "a - add new record",rn "d - delete record",rn "q - quit",rn NULL,rn;rnrnint getchoice(char *greet, char *choices[], FILE *in, FILE *out);rnint char_to_terminal(char char_to_write);rnrnint main()rnrn int choice = 0;rn FILE *input;rn FILE *output;rn struct termios initial_settings, new_settings;rnrn if (!isatty(fileno(stdout))) rn fprintf(stderr,"You are not a terminal, OK.\n");rn rnrn input = fopen("/dev/tty", "r");rn output = fopen("/dev/tty", "w");rn if(!input || !output) rn fprintf(stderr, "Unable to open /dev/tty\n");rn exit(1);rn rn tcgetattr(fileno(input),&initial_settings);rn new_settings = initial_settings;rn new_settings.c_lflag &= ~ICANON;rn new_settings.c_lflag &= ~ECHO;rn new_settings.c_cc[VMIN] = 1;rn new_settings.c_cc[VTIME] = 0;rn new_settings.c_lflag &= ~ISIG;rn if(tcsetattr(fileno(input), TCSANOW, &new_settings) != 0) rn fprintf(stderr,"could not set attributes\n");rn rnrn do rn choice = getchoice("Please select an action", menu, input, output);rn printf("You have chosen: %c\n", choice);rn while (choice != 'q');rnrn tcsetattr(fileno(input),TCSANOW,&initial_settings);rn exit(0);rnrnrnint getchoice(char *greet, char *choices[], FILE *in, FILE *out)rnrn int chosen = 0;rn int selected;rn int screenrow, screencol = 10;rnrn char **option;rn char *cursor, *clear;rnrn output_stream = out;rnrn setupterm(NULL,fileno(out), (int *)0);rn cursor = tigetstr("cup");rn clear = tigetstr("clear");rnrn screenrow = 4;rn tputs(clear, 1, char_to_terminal);rn tputs(tparm(cursor, screenrow, screencol), 1, char_to_terminal);rn fprintf(out, "Choice: %s", greet);rn screenrow += 2;rn option = choices; rn while(*option) rn tputs(tparm(cursor, screenrow, screencol), 1, char_to_terminal);rn fprintf(out,"%s", *option);rn screenrow++;rn option++;rn rnrn do rn selected = fgetc(in);rn option = choices;rn while(*option) rn if(selected == *option[0]) rn chosen = 1;rn break;rn rn option++;rn rn if(!chosen) rn tputs(tparm(cursor, screenrow, screencol), 1, char_to_terminal);rn fprintf(out,"Incorrect choice, select again\n");rn rn while(!chosen);rn tputs(clear, 1, char_to_terminal);rn return selected;rnrnrnint char_to_terminal(char char_to_write)rnrn if (output_stream) putc(char_to_write, output_stream);rn return 0;rnrnrnrn$ gcc menu5.crnrnmenu5.c:4:18: error: term.h: 没有那个文件或目录rnmenu5.c:5:20: error: curses.h: 没有那个文件或目录rnmenu5.c: In function ‘getchoice’:rnmenu5.c:69: warning: assignment makes pointer from integer without a castrnmenu5.c:70: warning: assignment makes pointer from integer without a castrnrnrnrnrnrn
Graphchi compile
when comping the examples, encounter the following error:rnrn./src/util/ioutil.hpp:35:18: fatal error: zlib.h: No such file or directorycompilation terminated.rnrnSolve:rnRun rnsudo apt-get install build-essentialrnsudo apt-get install zlib1g-devrnrnand then make again!
Compile问题
#include rnusing namespace std;rnclass Treernrn private:rn string par;rn public:rn Tree()rn rn par = "abc";rn rn void seed()rn rn cout << "seed la";rn rn;rnmain(int argc,char* argv[])rnrnrnrn我在dev c++下没有问题,但在linux用g++rng++ mytree.cpp -o mytree.exernrnrnmytree.cpp:6: syntax error before `;'rnmytree.cpp: In method `Tree::Tree ()':rnmytree.cpp:10: `par' undeclared (first use this function)rnmytree.cpp:10: (Each undeclared identifier is reported only once forrneach function it appears in.)rnrn到底怎回事,百思不解rn
Basic Compile
Basic 編譯器
computer compile
tech you how to <em>compile</em>,and use
jd-gui compile
一款纯绿色的java反编译软件,压缩完仅586KB。 解压可用,强大的反编译功能,可以把class文件编译成java文件,而且支持层级关系,在打开子类的情况下,直接点击父类名称,即可进入父类文件 轻巧方便~是我使用过最好的反编译软件~~ 还等什么呢?
saparately compile
使用编译器---Dev c++rnfile 1---Global.cpprnfile 2---Global1.cpprn//Global.cpprnrn#include rnusing namespace std;rnrnint globe;rnvoid func();rnint main() rn globe = 12;rn cout << globe << endl;rn func(); rn cout << globe << endl;rn rnrn//: Global1.cpp rnrnextern int globe; rnvoid func() rn globe = 47;rnrnrn无法编译Global1.cpprn怎么解决呢?请教。
网页设计——compile
网页设计-比较简洁,css+divde的简单网页,希望能得到你的喜欢。
compile CFLAG
gcc cflag parameter! if you need it ,download it and learn it!
vbox compile
这是个简单的vbox 编译文档 ,win7 64位系统
Onvif Compile
onvif 在linux下的编译命令,可网络在线编译
compile code
CSDN下载社区为广大用户提供的编译器
how to compile
#define PLMM_bf 1//漂亮妹妹之男友rn#define PLMM_PLlevel 100rn rnif(I love the plmm)rn rn if(MyMoney==0)rn rn if(MyTime==0)rn rn plmm.becomemy_gf(false);rn rn plmm.belongto_me(false);rn rn plmm.belongto_me(false);rn rnelsern plmm.belong(plmm_bf);rnrnreturn rn how can i do...;;;;;rn
compile出错!
装了Microsoft Visual Studio 6.0 Service Pack 4后,出现以下错误,请大家帮忙看看怎么解决,谢谢!rnCompiling...rnMyButton.cpprnc:\program files\microsoft visual studio\myprojects\ex_sdimy\mybutton.cpp(4) : fatal error C1853: 'Debug/Ex_SDIMy.pch' is not a pre<em>compile</em>d header file created with this <em>compile</em>rrnError executing cl.exe.rn
.Net.Framework3.5开发技术详解下载
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openwrt sdk part4下载
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51单片机STC89系列说明书下载
STC89C51RC/RD+系列单片机是宏晶科技??出的新一出的新一新一???高速/低功耗/超强抗干扰的高速/低功耗/超强抗干扰的单片高速/低功耗/超强抗干扰的单片单片单片 机,指令?码完全兼容传统8051单片机,128051单片机,12时钟/机器时钟/机器时钟/机器??????和6时钟/机器和6时钟/机器和6时钟/机器??????可可可?????????选选选???,,, HD版本和90C版本内部集成MAX810专用复位电路?? 1. 增强型8051单片机,6时钟/机器单片机,6时钟/机器6时钟/机器??????和12时钟/机器和12时钟/机器和12时钟/机器和12时钟/机器12时钟 相关下载链接:[url=//download.csdn.net/download/waybq/3041554?utm_source=bbsseo]//download.csdn.net/download/waybq/3041554?utm_source=bbsseo[/url]
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我们是很有底线的