我下载了sourcecode,编译asm文件的时候先是如下rnMicrosoft (R) 32-bit C/C++ Optimizing Compiler Version 12.00.8168 for 80x86rnCopyright (C) Microsoft Corp 1984-1998. All rights reserved.rnd_draw16.srn系统找不到指定的路径。rnMicrosoft (R) Macro Assembler Version 7.00.9466rnCopyright (C) Microsoft Corporation. All rights reserved.rn Assembling: .\Release\d_draw16.asmrn.\Release\d_draw16.asm(1) : error A2088: END directive required at end of filernrn怎么办？
(ebook - PDF - Programming) Abrash, Michael - Ramblings in Realtime (On the Quake 3D Engine) (2000).pdf
As for how to rethink the design, do it by pursuing whatever ideas occur to you, no matter how
off-the-wall they seem. Many of the truly brilliant design ideas I’ve heard over the years
sounded like nonsense at first, because they didn’t fit my preconceived view of the world.
Often, such ideas are in fact off-the-wall, but just as the news about Paradise’s chip sparked
Tom’s imagination, aggressively pursuing seemingly-outlandish ideas can open up new design
possibilities for you.
Case in point: The evolution of Quake’s 3-D graphics engine.
DescriptionnJinye is playing with cards. He has n cards in hand now. There is a number range from 1 to m writing on each card respectively.nThere is a card sequence in the deck. At the beginning the sequence is empty.nJinye will play for t rounds, at each round, Jinye will play one of these two operations:n1. select x y. x and y are both integer and x should between 1 and the number of cards in Jinye’s hand now, y should between 1 and the number of cards in the card sequence+1.That means Jinye insert the $x_th$ card in his hand into the card sequence’s $y_th$ position. For example, if the cards in Jinye’s hand is 2,3,3,6,1 now, and the card sequence is 2,2,5,4,3, after we play “select 4 2”, the cards in Jinye’s hand become 2,3,3,1, and the card sequence become 2,6,2,5,4,3.n2. pop. Pop up the cards in the card sequence’s right most and put it into the right most of Jinye’s hand. For example, if the cards in Jinye’s hand is 2,3,3,1 now, and the card sequence is 2,6,2,5,4,3, after we play “pop”, the cards in Jinye’s hand become 2,3,3,1,3 and the card sequence become 2,6,2,5,4.nThe card sequence should be empty after t rounds.nFor the card with number i writing on it, if it’s in card sequence now, its position in card sequence should never exceed $h_i$ at any moment.nThere are some limits between cards. If x is limited by y, that means if there is at least one card with number y in the card sequence now, the card with number x can not be insert into the card sequence. Note that x can be equal to y, that means there is at most one x in the card sequence.nIf there is no card can be insert into card sequence, the “select x y” operation is illegal.nIf there is no card in the card sequence now, the “pop” operation is illegal.nOur problem is, how many legal operate sequence can meet all the demand.nTwo operate sequences are consider different if there is a round they display different operations or there is a round they both display “select” but the parameters are different.nOutput the answer modulo 1000000009.n nInputnThe first line contains a single integer T, indicating the number of test cases.nEach test case begin with three integers n, m, and t, indicating the number of cards in Jinye’s hand now, the range of the number writing on card, the number of rounds this game will play.nNext line contain n integers $A_1,A_2, \ldots, A_n, A_i$ means the number writing on the $i_th$ cards.nNext line contain m integers $h_1,h_2, \ldots, h_m$, as described above.nNext line contain an integers f, indicating the number of limits between cards.nNext f lines, each line contains two integers x and y, means x is limited by y.nn[Technical Specification]n1 <= mn nOutputnFor each case, output contain one line, the number of answer.n nSample Inputnn1n1 1 2n1n1n0nn nSample Outputnn1
The FORTH programming language does not support floating-point arithmetic at all. Its author, Chuck Moore, maintains that floating-point calculations are too slow and most of the time can be emulated by integers with proper scaling. For example, to calculate the area of the circle with the radius R he suggests to use formula like R * R * 355 / 113, which is in fact surprisingly accurate. The value of 355 / 113 = 3.141593 is approximating the value of PI with the absolute error of only about 2*10^-7. You are to find the best integer approximation of a given floating-point number A within a given integer limit L. That is, to find such two integers N and D (1 < 10) with the precision of up to 15 decimal digits. The second line contains the integer limit L. (1 0?num:-num;rnrnrnrnfloat F(long &N,long D,float A)rnrn float t=abs((float)N/D-A);rn while(1)rn rn if(abs((float)(N+1)/D-A)>A>>D)rn rn T=D;rn for(d=1;d<=D;d++)rn rn N=A*d;rn t=F(N,d,A);rn if(t