用了delete []pBuf; 但是编译后还有乱码！

[chenhu_doc]

//没有注释，请见谅！

#include <iostream.h>
#include <strstrea.h>
char * parseString(char *pString)
{
istrstream inp(pString,0);
int aNumber;
float balance;
inp>>aNumber>>balance;
char * pBuffer=new char[128];
ostrstream outp(pBuffer,128);
outp<<"aNumber="<<aNumber
<<",balance="<<balance<<endl;
return pBuffer;
}
void main()
{
char *str="1234 100.35";
char *pBuf=parseString(str);
cout<<pBuf<<endl;
delete []pBuf;
}

[llf_hust]

#include <iostream.h>
#include <strstrea.h>
char * parseString(char *pString)
{
istrstream inp(pString,0);
int aNumber;
float balance;
inp>>aNumber>>balance;
char * pBuffer=new char[128];

ostrstream outp(pBuffer,128);

outp<<"aNumber="<<aNumber
<<",balance="<<balance<<'\0'<<endl;
return pBuffer;
}
int main()
{
char *str="1234 100.35";
char *pBuf=parseString(str);
cout<<pBuf<<endl;
delete []pBuf;
return 0;
}

[chenhu_doc]

to llf_hust() ( )
给一个解释萨 为什么一个'\0'就解决问题了呢？？

[llf_hust]

因为字符串要以\0'结尾，没有就会出现乱码。很明显你的pBuf因为没有'\0'才会出现乱码的呀，所以我就给它加了一个

[chenhu_doc]

o 原来如彼！！
谢了！！

[sankt]

up

[chenhu_doc]

赫赫

[sunbinkeke]

能不能再深一点解释为什么不加‘0’就会有乱码，c＋＋是怎么编译这个语句的