请高手帮忙看看！！！为什么以下代码利用internet上不能进行预览啦（页面上什么东西都没有，一片空白）？

nlw1984 2005-10-20 11:25:41

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>无标题文档</title>
<style title="text/css">

</style>
</head>

<body>
<?php
include_once("dbclass.php")
if($db->getfirst("select * from iptable where
voteip='$_SERVER['REMOTE_ADDR']'")){
echo"您已经投过票了，谢谢您的参与!";
}
if(!$action){
echo"<table width=200 boder=0 cellpadding=2 cellspacing=1>";
echo"<form action='' method='post' name='voteform' onsubmit='return checkform(this)'>";

$myitems=$db->query("select * from itemtable");
$itemNo=0;
while($myitem=$db->getarray($myitem)){
echo"<tr>
<td nowrap style='cursor:default'
onclick='voteform.check$itemNo.click()'>
<input name='check$itemNo' type='checkbox' value='$myitem [id]'>
$myitem[name]
</td>
<tr> \n";
}
echo'<tr>
<td>
<input name="action" type="hidden" value="vote"><br>
<input name="submit" type="submit" value="投票">
<input name="reset" type="reset" value="重置">
</td>
</tr>';
echo"\n</form>\n</table>";
?>
<script language="javascript">

</script>
<?php
}
else if($action="vote"){
$itemcount=$db->getfirst("select count(*) as count from itemtable");
$checkarray=array();
for($i=1;$i<=$itemcount["count"];$i++){
$mycheck="check$i";$mycheck=$$mycheck;
if($mycheck && $db->getfirst("select * from itemtable where id='$mycheck'")){
$checkarray[]=$mycheck;
}
}
if(count($checkarray)==2{
for($i=0;$i<count($checkarray);$i++){
$db->query("update itemtable set votes=votes+1 where id='$checkarray[$i]'");
}
$db->query("inset into iptable(voteip) values('$_SERVER['REMOTE_ADDR']')");
echo"投票成功，谢谢您的参与！";
}else{
echo"对不起，您只能投两个项目！";
}
}
?>
</body>
</html>

...全文