很困惑的问题，大家帮看以下

[sdqdzyb]

别人软件生成的。C文件，里面包含：
TSXFIELDINIT LOGIN[] = {

{ "HEAD", 0, 0,
TS_FIXED,
0,
20, 0, "",
0, 0, 0, "" },

{ "TXT_USER", 2, 0,
TS_FIXED,
0,
8, 0, "",
0, 0, 0, "" },

{ "TXT_PWD", 4, 0,
TS_FIXED,
0,
8, 0, "",
0, 0, 0, "" },

{ "TAIL", 6, 0,
TS_FIXED,
0,
20, 0, "",
0, 0, 0, "" },

{ "USER_NAME", 2, 9,
TS_ENTRY,
TF_AUTTAB,
8, 0, "",
0, 0, 0, "" },

{ "USER_PASSWORD", 4, 9,
TS_ENTRY | TS_XMIT,
0,
8, 0, "",
0, 0, 0, "" },

{ "", 0, 0, 0, 0, 0, 0, "", 0, 0, 0, "" }

};
他提供的结构定义如下：
struct tsxfieldinit {
char8 *name; /* field name */
int32 row; /* row number */
int32 col; /* column number */
int32 style; /* field style */
int32 flags; /* field flags */
int32 size; /* field size */
int32 len; /* length of current field data */
char8 *data; /* pointer to field data */
int32 ptype; /* pattern type (0=no pattern,1=visible,2=hidden) */
int32 psize; /* pattern size */
int32 plen; /* length of the current pattern */
char8 *pattern; /* pointer to pattern */
};

我把他放在VC CONSOLE环境下INCLUDE 该。C文件后，出现下面提示：
error C2440: 'initializing' : cannot convert from 'char [5]' to 'signed char *'
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
h:\antenna\antennascr.c(23) : error C2440: 'initializing' : cannot convert from 'char [1]' to 'long'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast
h:\antenna\antennascr.c(24) : error C2440: 'initializing' : cannot convert from 'char [1]' to 'long'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast

很困惑，大家给看看把

[sdqdzyb]

up

[MITSMI]

这个和编译器有关

手工转换一下

[sdqdzyb]

怎么手工转换

望指教

[vcmute]

.c .cpp都可以，不知道你的char8和int32定义是？
enum{TS_FIXED,TS_ENTRY,TF_AUTTAB,TS_XMIT};
typedef char char8;
typedef int int32;

[zxyjyzxyjy]

你在帮助索引里输入C2440查看信息，然后还可点击
Technote: Improved Conformance to ANSI C++
链接看更多的信息。一定对你有用的。

[菜牛]

char8是什么东西？

[sdqdzyb]

奇怪的是我用不支持MFC的CONSOLE方式，INCLUDE 后编译没问题

[sdqdzyb]

char8 就是以前老C 用的，别公司提供的DLL等组件就是用哪个写的

[sdqdzyb]

不是

#ifndef TEK_TYPES_DEFINED
typedef unsigned char uint8;
typedef unsigned short uint16;
typedef unsigned long uint32;
typedef signed char int8;
typedef signed short int16;
typedef signed long int32;
#endif

typedef int8 char8;
typedef uint8 uchar8;

[MITSMI]

不是说cannot convert from 'char [5]' to 'signed char *'

那你就显示转换一下这个指针吧

比如:
char ch[5] = "asdf" ;
signed char* tmp = (signed char*) ch ;