急：日期计算问题，我现在想通过年和周数算出一周内周一到周日的日期。

[紫罗兰Cherry]

现在需要传入年和周数，得到该周的周一和周五的日期。

如果可以有选择周数的日历就更好了。

谢谢！

[梅雪香]

<script language="JavaScript">
<!--
/*用相对不规则的字符串来创建日期对象,不规则的含义为:顺序包含年月日三个数值串,有间隔*/
String.prototype.createDate = function(){
var regThree = /^\D*(\d{2,4})\D+(\d{1,2})\D+(\d{1,2})\D*$/;
var regSix = /^\D*(\d{2,4})\D+(\d{1,2})\D+(\d{1,2})\D+(\d{1,2})\D+(\d{1,2})\D+(\d{1,2})\D*$/;
var str = "";
var date = null;
if(regThree.test(this)){
str = this.replace(/\s/g,"").replace(regThree,"$1/$2/$3");
date = new Date(str);
}
else if(regSix.test(this)){
str = this.match(regSix);
date = new Date(str[1],str[2]-1,str[3],str[4],str[5],str[6]);
}
if(isNaN(date)) return new Date();
else return date;
}

/*
* 功能:根据输入表达式返回日期字符串
* 参数:dateFmt:字符串,由以下结构组成
* yy:长写年,YY:短写年mm:数字月,MM:英文月,dd:日,hh:时,
* mi:分,ss秒,ms:毫秒,we:汉字星期,WE:英文星期.
* isFmtWithZero : 是否用0进行格式化,true or false
*/
Date.prototype.parseString = function(dateFmt,isFmtWithZero){
dateFmt = (dateFmt == null?"yy-mm-dd" : dateFmt);
isFmtWithZero = (isFmtWithZero == null?true : isFmtWithZero);
if(typeof(dateFmt) != "string" )
throw (new Error(-1, 'parseString()方法需要字符串类型参数!'));
var weekArr=[["星期日","星期一","星期二","星期三","星期四","星期五","星期六"],
["SUN","MON","TUR","WED","THU","FRI","SAT"]];
var monthArr=["JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"];
var str=dateFmt;
str = str.replace(/yy/g,this.getFullYear());
str = str.replace(/YY/g,this.getYear());
str = str.replace(/mm/g,(this.getMonth()+1).toString().fmtWithZero(isFmtWithZero));
str = str.replace(/MM/g,monthArr[this.getMonth()]);
str = str.replace(/dd/g,this.getDate().toString().fmtWithZero(isFmtWithZero));
str = str.replace(/hh/g,this.getHours().toString().fmtWithZero(isFmtWithZero));
str = str.replace(/mi/g,this.getMinutes().toString().fmtWithZero(isFmtWithZero));
str = str.replace(/ss/g,this.getSeconds().toString().fmtWithZero(isFmtWithZero));
str = str.replace(/ms/g,this.getMilliseconds().toString().fmtWithZeroD(isFmtWithZero));
str = str.replace(/we/g,weekArr[0][this.getDay()]);
str = str.replace(/WE/g,weekArr[1][this.getDay()]);
return str;
}
/*将一位数字格式化成两位,如: 9 to 09*/
String.prototype.fmtWithZero = function(isFmtWithZero){
if(isFmtWithZero)
return (this<10?"0"+this:this);
else return this;
}
String.prototype.fmtWithZeroD = function(isFmtWithZero){
if(isFmtWithZero)
return (this<10?"00"+this:(this<100?"0"+this:this));
else return this;
}

/* 功能 : 返回与某日期相距N天(N个24小时)的日期
* 参数 : num number类型 可以为正负整数或者浮点数,默认为1;
* type 0(秒) or 1(天),默认为秒
* 返回 : 新的PowerDate类型
*/
Date.prototype.dateAfter=function(num,type){
num = (num == null?1:num);
if(typeof(num)!="number") throw new Error(-1,"dateAfterDays(num,type)的num参数为数值类型.");
type = (type==null?0:type);
var arr = [1000,86400000];
var dd = this.valueOf();
dd += num*arr[type];
return new Date(dd);
}

//判断是否是闰年,返回true 或者 false
Date.prototype.isLeapYear = function (){
var year = this.getFullYear();
return (0==year%4 && ((year % 100 != 0)||(year % 400 == 0)));
}

//返回该月天数
Date.prototype.getDaysOfMonth = function (){
return (new Date(this.getFullYear(),this.getMonth()+1,0)).getDate();
}

//转换成大写日期(中文)
Date.prototype.getChinaDate = function(){
var year = this.getFullYear().toString();
var month= this.getMonth()+1;
var day = this.getDate();
var arrNum = ["零","一","二","三","四","五","六","七","八","九","十","十一","十二"];
var strTmp="";
for(var i=0,j=year.length;i<j;i++){
strTmp += arrNum[year.charAt(i)];
}
strTmp += "年";
strTmp += arrNum[month]+"月";
if(day<10)
strTmp += arrNum[day];
else if (day <20)
strTmp += "十"+arrNum[day-10];
else if (day <30 )
strTmp += "二十"+arrNum[day-20];
else
strTmp += "三十"+arrNum[day-30];
strTmp += "日";
return strTmp;
}
//日期比较函数,参数date:为Date类型,如this日期晚于参数:1,相等:0 早于: -1
Date.prototype.dateCompare = function(date){
if(typeof(date) != "object" || !(/Date/.test(date.constructor)))
throw new Error(-1,"dateCompare(date)的date参数为Date类型.");
var d = this.getTime() - date.getTime();
return d>0?1:(d==0?0:-1);
}

/*功能:返回两日期之差
*参数:pd PowerDate对象
* type: 返回类别标识.yy:年,mm:月,ww:周,dd:日,hh:小时,mi:分,ss:秒,ms:毫秒
* intOrFloat :返回整型还是浮点型值 0:整型,不等于0:浮点型
* output : 输出提示,如:时间差为#周!
*/
Date.prototype.calDateDistance = function (date,type,intOrFloat,output){
if(typeof(date) != "object" || !(/Date/.test(date.constructor)))
throw new Error(-1,"calDateDistance(date,type,intOrFloat)的date参数为Date类型.");
type = (type==null?'dd':type);
if(!((new RegExp(type+",","g")).test("yy,mm,ww,dd,hh,mi,ss,ms,")))
throw new Error(-1,"calDateDistance(pd,type,intOrFloat,output)的type参数为非法.");
var iof = (intOrFloat==null?0:intOrFloat);
var miSecMain = this.valueOf();
var miSecSub = date.valueOf();
var num=0;
switch(type){
case "yy": num = this.getFullYear() - date.getFullYear(); break;
case "mm": num = (this.getFullYear() - date.getFullYear())*12+this.getMonth()-date.getMonth(); break;
case "ww": num = ((miSecMain-miSecSub)/7/86400000).fmtRtnVal(iof); break;
case "dd": num = ((miSecMain-miSecSub)/86400000).fmtRtnVal(iof); break;
case "hh": num = ((miSecMain-miSecSub)/3600000).fmtRtnVal(iof); break;
case "mi": num = ((miSecMain-miSecSub)/60000).fmtRtnVal(iof); break;
case "ss": num = ((miSecMain-miSecSub)/1000).fmtRtnVal(iof); break;
case "ms": num = (miSecMain-miSecSub);break;
default: break;
}
if(output)
return output.replace(/#/g," "+num+" ");
else return num;
}
//返回整数或者两位小数的浮点数
Number.prototype.fmtRtnVal = function (intOrFloat){
return (intOrFloat == 0 ? Math.floor(this) : parseInt(this*100)/100);
}
//根据当前日期所在年和周数返回周日的日期
Date.prototype.RtnByWeekNum = function (weekNum){
if(typeof(weekNum) != "number")
throw new Error(-1,"RtnByWeekNum(weekNum)的参数是数字类型.");
var date = new Date(this.getFullYear(),0,1);
var week = date.getDay();
week = (week==0?7:week);
return date.dateAfter(weekNum*7-week,1);
}
//-->
</script>

<script language="JavaScript">
<!--
var date1 = "2005-11-1 00:00:00".createDate();
var date2 = "2005-11-3 00:00:00".createDate();
//alert(date2.calDateDistance(date1,"hh"));
alert(date1.RtnByWeekNum(10).parseString("yy-mm-dd"));
//-->
</script>


我要把有限的生命投入到无限的为人民回贴事业中去!
谁会申请域名?帮我申请一个,最好是www.meixx.com/net/org,不要二级和三级的!
还有好的免费空间,谁知道?帮忙啊!

[jxjjljf]

m

[紫罗兰Cherry]

已搞定，代码如下：
/*
* Function: Return date string according to the expression.
* Parameters: dateFmt: string, including following:
* yy: year (2005). mm month(02) dd: day(30).
* isFmtWithZero: use 0 to format or not.(true/false).
*/

function ParseString(date1,dateFmt,isFmtWithZero){
dateFmt = (dateFmt == null?"yy-mm-dd" : dateFmt);
isFmtWithZero = (isFmtWithZero == null?true : isFmtWithZero);

if(typeof(dateFmt) != "string" )
throw (new Error(-1, 'ParseString()·½·¨ÐèÒª×Ö·û´®ÀàÐͲÎÊý!'));

var str=dateFmt;

str = str.replace(/yy/g,date1.getFullYear());
str = str.replace(/mm/g,(date1.getMonth()+1).toString().fmtWithZero(isFmtWithZero));
str = str.replace(/dd/g,date1.getDate().toString().fmtWithZero(isFmtWithZero));

return str;
}

/** 9 --> 09, add 0 to format number. */

String.prototype.fmtWithZero = function(isFmtWithZero){
if(isFmtWithZero)
return (this<10?"0"+this:this);
else return this;
}

/* Function: Return the date after N days of this date.
* Parameters: num number type, possitive or negative, default is 1.
* type 0(second) or 1(day). default is 0.
* Return: the date.
*/

Date.prototype.dateAfter=function(num,type){
num = (num == null?1:num);
if(typeof(num)!="number") throw new Error(-1,"dateAfterDays(num,type)µÄnum²ÎÊýΪÊýÖµÀàÐÍ.");
type = (type==null?0:type);
var arr = [1000,86400000];
//24*60*60*1000 = 86400000(millisecond).
var dd = this.valueOf();
dd += num*arr[type];

return new Date(dd);
}

//Return the date of Sunday in the week number.
function GetDateByWeekNum(Year,weekNum){
//if(typeof(weekNum) != "number")
// throw new Error(-1,"GetDateByWeekNum(Year,weekNum)µÄ²ÎÊýÊÇÊý×ÖÀàÐÍ.");
//var date = new Date(this.getFullYear(),0,1);
var date = new Date(Year,0,1);

var week = date.getDay();

week = (week==0?7:week);

return date.dateAfter(weekNum*7-week-1,1);
}

谢谢各位！