二维字符串数组作为函数的参数该如何表示呢？(只限于用标准C方式)

[sj971059]

为了测试功能，这是我写的测试程序。

这里的执行流程是先把g_szMsgs赋给szMsgs，然后通过调用funcDealSendRows()函数，想把
szMsgs变成一维字符串数组。现在的问题就是怎么定义funcDealSendRows()的二维数组参数？

#include <stdio.h>
#include <string.h>
#include <iostream>
using namespace std;

#define SQLNUM 10
#define S_MSG_LENTH 2000
#define MSG_LENGTH SQLNUM * S_MSG_LENTH

char g_szMsgs[SQLNUM][S_MSG_LENTH+1] = { "insert into table1 values....;",
"insert into table2 values....;",
"insert into table3 values....;",
"insert into table4 values....;",
"insert into table5 values....;",
"insert into table6 values....;",
"insert into table7 values....;",
"insert into table8 values....;",
"insert into table9 values....;",
"insert into table10 values....;" };

void funcDealSendRows(int, char*);

void main()
{
int lpMQID [SQLNUM];
int iNum = 0;
char szMsg [SQLNUM*(S_MSG_LENTH+1)];
char szMsgRecv [S_MSG_LENTH+1];
char szMsgs [SQLNUM][S_MSG_LENTH+1];
int i;
int j;
int flag;

szMsg[0] = '\0';


for (i=0; i<SQLNUM; i++) {
for (j=0; j<(S_MSG_LENTH+1); j++) {
szMsgs[i][j] = g_szMsgs[i][j];
}
}

cout << "拼成SQL语句串之前内容 :" << endl;
for (i=0; i<SQLNUM; i++) {
for (j=0; j<(S_MSG_LENTH+1); j++)
if (szMsgs[i][j] != '\0')
cout << szMsgs[i][j];
cout << endl;
}

/*将10条分号结尾的SQL语句组合成一个字符串*/
// cout << "若干条SQL语句拼成一串 :" << endl;
// for (i=0; i<SQLNUM; i++) {
// strcat(szMsg,szMsgs[i]);
// }
// szMsg[sizeof(szMsg)] = '\0';
// cout << szMsg << endl;

funcDealSendRows(SQLNUM,szMsgs);

/*从szMsg中解析出有多少条字符串,重新放入字符串数组中显示*/
cout << "从SQL串中取出后 :" << endl;
flag=0;
for (i=0; i<sizeof(szMsg); i++) {
if (szMsg[i] == ';') {
strncpy(szMsgRecv,szMsg+flag,i-flag+1);
szMsgRecv[i-flag+1] = '\0';
flag=i+1;
cout << szMsgRecv << endl;
}
}
}

void funcDealSendRows(int iLen, char* szMsgs)
{
char szMsgMqsend [ SQLNUM*(S_MSG_LENTH + 1) ];
for (int i=0; i<iLen; i++) {
strcat(szMsgMqsend, szMsgs+i);
}
szMsgMqsend[sizeof(szMsgMqsend)] = '\0';
cout << szMsgMqsend << endl;
}

[菜牛]

void funcDealSendRows(int iLen, char** szMsgs)

[sj971059]

ok.我先试试。