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分享表单提交问题
一个表单里有俩个以上的button,假如是button1,button2,...,我想在按button1就提交,其他的暂时不管.我该怎么做,才能让点button1提交.
还有,表单提交之后,把显示结果就在当前页的下方显示,我又该怎么做?
还有,表单提交之后,把显示结果就在当前页的下方显示,我又该怎么做?
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afei0220 2005-11-29
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安全一点的话就:
<body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='text' name='test2'>
<input type='button' onclick='document.form.submit()'>
<input type="button">
</form>
<?
if(isset$_POST['test']) { //add this to check
echo $_POST['test'];
echo $_POST['test2'];
}
?>
</body>
<body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='text' name='test2'>
<input type='button' onclick='document.form.submit()'>
<input type="button">
</form>
<?
if(isset$_POST['test']) { //add this to check
echo $_POST['test'];
echo $_POST['test2'];
}
?>
</body>
Zi_Yuan 2005-11-28
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<body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='button' onclick='document.form.submit()'>
<input type="button">
</form>
<?
echo $_POST['test'];
?>
</body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='button' onclick='document.form.submit()'>
<input type="button">
</form>
<?
echo $_POST['test'];
?>
</body>
Zi_Yuan 2005-11-28
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<body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='submit' onclick='document.form.submit()'>
</form>
<?
echo $_POST['test'];
?>
</body>
<form action="cc.php" method=post name=form>
<input type='text' name='test'>
<input type='submit' onclick='document.form.submit()'>
</form>
<?
echo $_POST['test'];
?>
</body>
zalvsa 2005-11-28
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<form>
<input type='text' name='test'>
<input type='button' onclick='this.form.submit()'>
</form>
<?
echo $test;
?>
<input type='text' name='test'>
<input type='button' onclick='this.form.submit()'>
</form>
<?
echo $test;
?>
