参考,XMLHTTP方式:
var thpstr = "xxx";
var thInfo = "abc="+escape(thpstr);
var objth = new ActiveXObject("Microsoft.XMLHTTP");
objth.open("POST","请求的页.asp",false);
objth.setRequestHeader("Content-Type","application/x-www-form-urlencoded")
objth.send(thInfo);
//alert(unescape(objth.responseText));请求后目标页返回的内容
objth.abort();