很急的问题,在线等

lyx7796 2006-02-24 10:12:53

我通过
label2.Attributes.Add("onMouseDown", "this.innerHTML=document.form1.Select1.options[document.form1.Select1.selectedIndex].value")给label里的text赋值了
怎么样才能把这个值在服务器端取出来那???

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zhangym365 2006-02-25

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在你赋值给lable控件的同时，把对象的值赋值给一个隐含的对象，将值回传
。
lable对象的值是不提交到服务器的。你可以通过textbox、hiddenfield等控件进行回传。

singlepine 2006-02-24

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//html

<HTML>
<HEAD>
<title>WebForm7</title>
<script language="javascript">
function getData()
{
var province=document.getElementById("SELECT1");
var pindex = province.selectedIndex;
var pValue = province.options[pindex].value;
var pText = province.options[pindex].text;

document.getElementById("<%=Label1.ClientID%>").innerText=pText;
}

</script>
</HEAD>
<body MS_POSITIONING="GridLayout">
<form id="Form1" method="post" runat="server">
<asp:Label id="Label1" style="Z-INDEX: 101; LEFT: 240px; POSITION: absolute; TOP: 48px" runat="server">Label</asp:Label><SELECT id="SELECT1" style="Z-INDEX: 102; LEFT: 352px; POSITION: absolute; TOP: 40px" runat="server">
<OPTION value="1">男</OPTION>
<OPTION value="0" selected>女</OPTION>
</SELECT></FONT>
<asp:Button id="Button1" style="Z-INDEX: 103; LEFT: 248px; POSITION: absolute; TOP: 104px" runat="server"
Text="Button"></asp:Button>
</form>
</body>
</HTML>

//cs
protected System.Web.UI.WebControls.Label Label1;
protected System.Web.UI.HtmlControls.HtmlSelect SELECT1;
protected System.Web.UI.WebControls.Button Button1;
private void Page_Load(object sender, System.EventArgs e)
{
if(!Page.IsPostBack)
{
Label1.Attributes.Add("onmousedown", "getData();");
}
}

private void Button1_Click(object sender, System.EventArgs e)
{
string script="<script language='javascript'>alert('"+Request.Form["SELECT1"]+"');</script>";
Page.RegisterStartupScript("",script);
}

Jianyi 2006-02-24