求GDI+中DrawCurve函数使用方法（POINT和Point）

[howard]

POINT *curPoints = new POINT[i_Points];
for(int j=0;j<i_Points;j++)
{
curPoints[j].x=curx;
curPoints[j].y=cury;
}
Point* pcurvePoints = curPoints;

graphics.DrawCurve(&pen,pcurvePoints,i_Points);


=====================
我还不会如何动态创建Point类型的数组，有什么方法可以把POINT转换成Point类型么？
GDI中Point好象只能这样声明（MSDN中看到的）
=====================

Point point1(100, 100);
Point point2(200, 50);
Point point3(400, 10);
Point point4(500, 100);

Point curvePoints[4] = {
point1,
point2,
point3,
point4};

Point* pcurvePoints = curvePoints;

graphics.DrawCurve(&greenPen, curvePoints, 4, 1.0);

[howard]

。。。。。。。。天啊，居然是大写的X和Y。哎~~~~~~~~~

[howard]

CDC *dc;
dc=this->GetDC();
Graphics graphics(dc->m_hDC);
//Pen pen(penColor,i_penWidth);
Pen pen(Color::Green,5);

Point pt1(320,380);
Point pt2(420,540);
Point pt3(620,440);
Point pt4(580,220);
Point pt5(380,300);
Point pt6(400,360);
Point pt7(320,380);
Point curPoints[7]=
{
pt1,pt2,pt3,pt4,pt5,pt6,pt7
};

graphics.DrawClosedCurve(&pen,curPoints,7);

这样就能画出图样来，可是下面的代码就画不出来，curPoints数值都是一样的呀
Point *curPoints = new Point [i_Points];
for(int j=0;j<i_Points;j++)
{//
x=...;
y=...;
//
curPoints[j].X=x;
curPoints[j].Y=y;
}

graphics.DrawClosedCurve(&pen,curPoints,i_Points);
还是说Point *curPoints = new Point [i_Points];这样创建Point数组行不通？

[howard]

最后顶一次，我舍了一个断点，运行看了一下，如果手动创建的话，那么就没问题，
如果是Point *curPoints = new Point [i_Points];这样创建出来的，好象数组里只有1个值。但是我FOR循环的时候还是可以取去里面的XY的。真奇怪

[iori_wen]

up

[howard]

谁能帮帮我啊，着急啊

[dch4890164]

POINT *curPoints = new POINT[i_Points];
这个不就是动态创建嘛!

[howard]

对呀，可是POINT类型的不能使用在DrawCurve里啊，DrawCurve需要使用Point类型的。如何转换呢？

[howard]

error C2664: 'enum Gdiplus::Status __thiscall Gdiplus::Graphics::DrawCurve(const class Gdiplus::Pen *,const class Gdiplus::PointF *,int)' : cannot convert parameter 2 from 'struct tagPOINT *' to 'const cla
ss Gdiplus::PointF *'
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
Error executing cl.exe.

[昊叔]

Point* pcurvePoints = new Point[i_Points];
for(int j=0;j<i_Points;j++)
{
pcurvePoints [j].X=curx;
pcurvePoints [j].Y=cury;
}

graphics.DrawCurve(&pen,pcurvePoints,i_Points);

[howard]

自己 up

[wlwlxj]

ding

[Tan18]

应该可以吧，我用过
PointF* pts = new PointF(nPointCount);
gs->DrawLines();
没有问题