求解释该段代码含义

[richard_ma]

if (hibyte == 0) {
for (int i = count ; i-- > 0 ;) {
value[i] = (char) (ascii[i + offset] & 0xff);
}
} else {
hibyte <<= 8;
for (int i = count ; i-- > 0 ;) {
value[i] = (char) (hibyte | (ascii[i + offset] & 0xff));
}
}
Note:
int hibyte 为Unicode码高8位
char value[] 为字符型数组
int count 为字符数组长度，即char value = new char[count]

求解该段代码位操作的含义

[Fifotom]

应该是把一个ascii编码的字符数组转换为unicode编码吧，
ascii[i + offset] & 0xff该句完成将ascii[i + offset]的高8位请0
hibyte <<= 8;将高8位右移8位
hibyte | (ascii[i + offset] & 0xff)
该句在hibyte完成右移，ascii[i + offset]高8位被清0之后，其实相当于
hibyte + (ascii[i + offset] & 0xff)

[图门的世界]

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