php 读取文件内容 问题

[swh001]

在/opt/test/test.txt格式如下：
name:&test&
Rname:&testtest&
Rrealname:&woshitest&

如何在上面文本内容中抽取woshitest,也就是说我打开这个文本把woshitest赋值给$realname


echo $realname;//输出为woshitest

[wasuka]

name:&test&
Rname:&testtest&
Rrealname:&woshitest&

$file = fopen("/opt/test/test.txt","r+");
while($str = fgets($file,9999))
{
$v = explode(":",$str);
$key = $v[0];
$$key = $v[1];
}
echo Rrealname

[wasuka]

更正一下：最后一样应为：

echo $Rrealname;

少了个“$”

[swh001]

输出为&woshitest&
我想要的输出内容是两头没有&

[wasuka]

没注意，呵呵

echo ereg_replace("\&","",$str);

[swh001]

谢谢结贴

[Cain]

<?php
$content = file("/opt/test/test.txt");
foreach ($content as $lineNum => $line) {
if (preg_match("/([[:alpha:]]+):&(woshitest)&/", $line, $matches)) {
$$matches[1] = $matches[2];
}
}

echo $Rrealname;
?>