关于函数指针被赋值时候 右值与左值不一样的问题

[tianziyulu]

详细描述在代码注释中

#include "stdio.h"

typedef int (*PNFV)() ;

int temp1()
{
return printf( "temp1\n" );
}

int temp2()
{
return printf( "temp2\n" );
}

int temp()
{
static PNFV temp = 0;
if ( temp == 0 )
{
temp = temp1; \\此处不管是 temp=&temp1 还是temp = \\ = temp1，temp的值都是一样，但跟temp1不同？何解？？
temp();
}
else if ( temp == temp1 )
{
temp = &temp2;
\\同上；
temp();
}


return 0;
}

int main()
{
printf( "The address of temp1 is %x\n", temp1 );
printf( "The address of temp2 is %x\n", temp2 );
temp();
printf( "The address of temp is %x\n", temp );
temp();
printf( "The address of temp is %x\n", temp );
return 0;
}

[gudulyn]

不用说了

[goodluckyxl]

temp 你定义的有问题
你的内部变量和自身所在的函数名字相同
内部static作用范围并非全局
而函数名字temp地址却是全局可见
所以在main中的temp永远为temp函数的地址
#include <stdio.h>
#include <stdlib.h>
#include "stdio.h"

typedef int (*PNFV)() ;
static PNFV tem = 0;
int temp1()
{
return printf( "temp1\n" );
}

int temp2()
{
return printf( "temp2\n" );
}

int temp()
{

if ( tem == 0 )
{
tem = temp1; //此处不管是 temp=&temp1 还是temp = \\ = temp1，temp的值都是一样，但跟temp1不同？何解？？
tem();
}
else if ( tem == temp1 )
{
tem = &temp2;
//同上；
tem();
}


return 0;
}

int main()
{
printf( "The address of temp1 is %x\n", temp1 );
printf( "The address of temp2 is %x\n", temp2 );
temp();
printf( "The address of temp is %x\n", tem );
temp();
printf( "The address of temp is %x\n", tem );
return 0;
}

[hslinux]

The address of temp1 is 40100a
The address of temp2 is 40100f
temp1
The address of temp is 401005
temp2
The address of temp is 401005

楼主的代码在VC6.0里运行的结果，不知道这个是不是楼主想要的结果。
temp()里与temp()同名的变量把temp()屏蔽了，局部变量优先于全局变量.