高手进,请教DES算法,帮忙看看,急啊!分不够在加!!解决后在送100
int DES(unsigned char *bufferin,unsigned char *bufferout, unsigned char *key,long mode)
{
//密钥变换为56字节(去掉校验位)
static unsigned char pc1[56] = {
56, 48, 40, 32, 24, 16, 8,
0, 57, 49, 41, 33, 25, 17,
9, 1, 58, 50, 42, 34, 26,
18, 10, 2, 59, 51, 43, 35,
62, 54, 46, 38, 30, 22, 14,
6, 61, 53, 45, 37, 29, 21,
13, 5, 60, 52, 44, 36, 28,
20, 12, 4, 27, 19, 11, 3 };
//56字节变换为48 字节(数据压缩)
static unsigned char pc2[48] = {
13, 16, 10, 23, 0, 4,
2, 27, 14, 5, 20, 9,
22, 18, 11, 3, 25, 7,
15, 6, 26, 19, 12, 1,
40, 51, 30, 36, 46, 54,
29, 39, 50, 44, 32, 47,
43, 48, 38, 55, 33, 52,
45, 41, 49, 35, 28, 31 };
//32字节变换为48字节(数据扩展)
static unsigned char exp[48] = {
31, 0, 1, 2, 3, 4,
3, 4, 5, 6, 7, 8,
7, 8, 9, 10, 11, 12,
11, 12, 13, 14, 15, 16,
15, 16, 17, 18, 19, 20,
19, 20, 21, 22, 23, 24,
23, 24, 25, 26, 27, 28,
27, 28, 29, 30, 31, 0 };
//64位数据IP(Initial Permutation)变换表
static unsigned char ip[64] = {
57, 49, 41, 33, 25, 17, 9, 1,
59, 51, 43, 35, 27, 19, 11, 3,
61, 53, 45, 37, 29, 21, 13, 5,
63, 55, 47, 39, 31, 23, 15, 7,
56, 48, 40, 32, 24, 16, 8, 0,
58, 50, 42, 34, 26, 18, 10, 2,
60, 52, 44, 36, 28, 20, 12, 4,
62, 54, 46, 38, 30, 22, 14, 6 };
//数据逆置换(Final Permutation)
static unsigned char ip_1[64] = {
39, 7, 47, 15, 55, 23, 63, 31,
38, 6, 46, 14, 54, 22, 62, 30,
37, 5, 45, 13, 53, 21, 61, 29,
36, 4, 44, 12, 52, 20, 60, 28,
35, 3, 43, 11, 51, 19, 59, 27,
34, 2, 42, 10, 50, 18, 58, 26,
33, 1, 41, 9, 49, 17, 57, 25,
32, 0, 40, 8, 48, 16, 56, 24 };
//Permutation P
static unsigned char pp[32] = {
15, 6, 19, 20,
28, 11, 27, 16,
0, 14, 22, 25,
4, 17, 30, 9,
1, 7, 23, 13,
31, 26, 2, 8,
18, 12, 29, 5,
21, 10, 3, 24 };
/* INITIALIZE THE TABLES */
/* Table - s1 */
static unsigned char s1[4][16] = {
14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,
0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,
4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,
15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13 };
/* Table - s2 */
static unsigned char s2[4][16] = {
15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,
3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,
0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,
13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9 };
/* Table - s3 */
static unsigned char s3[4][16] = {
10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,
13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,
13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,
1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12 };
/* Table - s4 */
static unsigned char s4[4][16] = {
7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,
13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,
10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,
3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14 };
/* Table - s5 */
static unsigned char s5[4][16] = {
2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,
14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,
4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,
11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3 };
/* Table - s6 */
static unsigned char s6[4][16] = {
12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,
10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,
9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,
4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13 };
/* Table - s7 */
static unsigned char s7[4][16] = {
4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,
13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,
1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,
6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12 };
/* Table - s8 */
static unsigned char s8[4][16] = {
13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,
1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,
7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,
2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11 };
/* 密钥生成中的循环左移位的累计次数*/
static unsigned char totrot[] = {1,2,4,6,8,10,12, 14, 15, 17, 19, 21, 23, 25, 27, 28 };
/*----------------------------------------------*/
//long mode = 1; //模式,1:加密,2:解密
//unsigned char bufferin[9], bufferout[9]; //明文,密文
/*----------------------------------------------*/
long i, j, k;
long rotshift; //密钥移位次数
//long keylen, buflen; //密钥长度,明文长度
unsigned char keybuf[65]; //密钥,密钥64字节缓冲区
unsigned char keyreal[57], keys[17][49]; //实际使用56字节密钥,48字节密钥数组
unsigned char srcbuf[65], dstbuf[65]; //明文,密文64字节缓冲区
unsigned char L[17][33], R[17][33], LR[65], RL[65]; //加密时临时数据左右两部分
unsigned char E[17][49]; //R数组的扩展数据
unsigned char B[9][7], BB[33], P[33]; //E和K异或后的缓冲数组
unsigned char C[17][29], D[17][29], CD[57]; //56字节密钥的左右两部分
unsigned char temp1, temp2, m, n, x;
//1.变换密钥
//密钥不足8字节则用0补足(或自定义)
//keylen = strlen((const char*)key);
//if(keylen<8)
// memset(key+keylen, 0, (8-keylen));
//将8字节密钥转换为64字节字串
for(i=0;i<8;i++)
{
j = *(key+i);
keybuf[8*i] = (j / 128) % 2;
keybuf[8*i+1] = (j / 64) % 2;
keybuf[8*i+2] = (j / 32) % 2;
keybuf[8*i+3] = (j / 16) % 2;
keybuf[8*i+4] = (j / 8) % 2;
keybuf[8*i+5] = (j / 4) % 2;
keybuf[8*i+6] = (j / 2) % 2;
keybuf[8*i+7] = (j / 1) % 2;
}
//根据pc1进行变换成56字节,去掉奇偶校验位
for(i=0;i<56;i++)
{
keyreal[i] = keybuf[pc1[i]];
}
//将56字节密钥分为左右两部分C[0],D[0]
for(i=0;i<28;i++)
{
C[0][i] = keyreal[i];
D[0][i] = keyreal[i+28];
}
//循环16次(i从1开始)
for(i=1;i<17;i++)
{
//根据加密或解密确定密钥顺序
if(mode) //加密
rotshift = totrot[i-1];
else //解密
rotshift = totrot[16-i];
//1)左移固定位数得到C[i]和D[i];
for(j=0;j<28;j++)
{
C[i][j] = C[0][j];
D[i][j] = D[0][j];
}
for(j=0;j<rotshift;j++)
{
temp1 = C[i][0];
temp2 = D[i][0];
for(k=0;k<27;k++)
{
C[i][k] = C[i][k+1];
D[i][k] = D[i][k+1];
}
C[i][27] = temp1;
D[i][27] = temp2;
}
//2)将C[i]D[i]用pc2化简为48位k[i];
for(j=0;j<28;j++)
{
CD[j] = C[i][j];
CD[j+28] = D[i][j];
}
for(j=0;j<48;j++)
{
keys[i][j] = CD[pc2[j]];
}
}