关于文件打开的问题

[huyu361]

xlapp.Application.Workbooks.Open('c:\file1.xls')
我想打开自己可以选择文件而不是固定位置 , 请问各位大侠怎么改程序呀!!
谢谢!!!

[霖湘凝]

string ls_path, ls_file
int li_rc
li_rc = GetFileOpenName("打开",ls_path,ls_file, "DOC", &
+ "Text Files (*.TXT),*.TXT," &
+ "Doc Files (*.DOC),*.DOC," &
+ "All Files (*.*), *.*", "C:\My Documents", 32770)
If li_rc <> 1 Then return

xlapp.Application.Workbooks.Open(ls_path)

[huyu361]

谢谢高手了感谢

[mnsiii]

please give score and end this page~~