Access97,Access2000,MDB 数据库密码破解C#程序（分享）

wang51346 2006-06-17 02:27:01

// 根据网上经验和方法用C#做一个破解程序
// 本程序最多取16位密码
using System.IO;
using System.Windows.Forms;
class Access
{
// 获取密码
static string GetPassword(string file)
{ // 未加密的文件0x42开始至0x61之前的每间隔一字节的数值
byte[] baseByte = { 0xbe,0xec,0x65,0x9c,0xfe,0x28,0x2b,0x8a,0x6c,0x7b,0xcd,0xdf,0x4f,0x13,0xf7,0xb1, };
byte flagByte = 0x0c; // 标志 0x62 处的数值
string password = "";
try
{
FileStream fs = File.OpenRead(file);
fs.Seek(0x14, SeekOrigin.Begin);
byte ver = (byte)fs.ReadByte(); // 取得版本, 1为Access2000, 0为Access97
fs.Seek(0x42, SeekOrigin.Begin);
byte[] bs = new byte[33];
if (fs.Read(bs, 0, 33) != 33) return "";
byte flag = (byte)(bs[32] ^ flagByte);
for(int i = 0; i < 16; i++)
{
byte b = (byte)(baseByte[i]^bs[i*2]);
if (i%2==0 && ver==1) b ^= flag; //Access 2000
if (b > 0) password += (char)b;
}
}
catch {}
return password;
}

// 主入口
static void Main()
{
OpenFileDialog f = new OpenFileDialog();
if (f.ShowDialog() != DialogResult.OK) return;
MessageBox.Show("密码:[" + GetPassword(f.FileName) + "]", "密码");
}
}

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