谁来帮我做一道简单的编程题?(英文)(在线等)

[qingyun1136]

Master a simple Java programming challenge (STATUS: NOT PASSED)

As the principal engineer of an HTTP web server, you are responsible for implementing the request processing subsystem of the server.
An incoming request for a specific resource, identified by an URI, must be dispatched to the appropriate handler according to the server configuration which maps URIs to request handlers. 'HandlerFactory.getHandler' must be implemented:

public class HandlerFactory
{
public String getHandler(String[] config, String requestUri)
{
}
}

The string array 'config' contains URI patterns and handler names. Two consecutive values form a key-value pair comprised of URI pattern and handler. 'requestUri' represents an incoming request, the URI to match against the configured handlers. 'getHandler' must return the correct handler for a given URI as a string value.

An URI pattern never contains wildcards and represents the start of an URI string, a prefix. Matching must be implemented accordingly. The handler with the longest matching URI pattern wins if more than one pattern matches. If no handler can be found, "cJGHAec" must be returned.

Example input:

String[] config: { "/", "MainServlet", "/nav", "NavigationServlet" }
String requestUri: "/nav/test"

Correct result: "NavigationServlet"

In this example, the configuration contains a mapping of "/" to "MainServlet" and "/nav" to "NavigationServlet". In the case of an incoming URI "/nav/test.nav", "NavigationServlet" is the correct choice because its pattern is longer than that of "MainServlet".


public class HandlerFactory
{
public String getHandler(String[] config, String requestUri)
{
//To do
;
}
}

[wangshenhai]

public String getHandler(String[] config, String requestUri){
String tmpstr = null;
String ru = requestUri;
int flag = 0;
int lastflag = 0;
int index = 0;
int i = 0;
for(i=0; i<config.length; i+=2){
flag = 0;
tmpstr = config[i];
for(int j=0; j<ru.length();j++){
if(tmpstr.length()>j){
if(tmpstr.substring(0,j+1).equalsIgnoreCase(ru.substring(0,j+1))){
flag++;
}
}
}
if(lastflag<flag){
lastflag = flag;
index = i;
}

}
if(lastflag==0)
return "cJGHAec";
return config[index+1];
}
你是不是就需要这样的效果啊？

[seu_cose]

so long...