新手系列之二：大家来看看这段代码有什么问题？？？？

[yaccor]

<?php
include "conn.php";
$content=$_POST["content"];
if ($content!="")
{
$mysql_link=mysql_connect($host,$user,$password);
mysql_select_db($bdb,$mysql_link);
$query="select * from t_games where gamesname='$content'";
mysql_query($query);
echo("<script type='text/javascript'>location.href='searchgamesaction.php';</script>");
mysql_close();
exit;
}
else
{
echo("<script type='text/javascript'> alert('Please input the content!');location.href='index.php';</script>");
}
?>


代码好象总是只执行else部分，原因何在？？？

[xuzuning]

不是在表单提交后执行或表单书写有误

[yaccor]

<form method="POST" action="searchaction.php">
<p><input type="text" name="content" size="30">
<input type="submit" value="search" name="B1"></p>
</form>

以上是我表单的代码，应该没问题吧

[xuzuning]

<?php
include "conn.php";
echo $content=$_POST["content"]; //检查一下是否有值
....

[caotian2000]

应该是if ($content!=="") 两个等号这样才对，要不是赋值的意思

[固执的染色体]

$content = $_GET["content"]; ??

[niohe]

if ($content!=="")

[yaccor]

谢谢大哥们，
是if ($content!=="")出了问题，给分了