如何在server端打印jsp返回的html页面源代码？

launch401 2006-07-18 05:01:05

我想放在servlet filter里面做，但是不知道如何实现。

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silverseven7 2006-07-25

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launch401 2006-07-18

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感谢kevinliuu提供思路，现在已经能够实现了，下面是filter的代码，因为http请求的话可能是servlet/jsp或者图片等资源，所以在web.xml里面不能写<url-pattern>/*</url-pattern>，我用的是类似于struts的统一入口servlet，所以我的url-pattern就指向那个统一入口了：

public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain)
throws IOException, ServletException {
HttpServletRequest req = (HttpServletRequest)request;
String requestUrl = req.getRequestURL().toString();
String requestQuery = req.getQueryString();
System.out.println("requetURL:"+requestUrl);
System.out.println("requestQuery:"+requestQuery);
System.out.println("###########begin watch filter###################");
String test = request.getParameter("test");
System.out.println("test:" + test);

if (test == null){
//如果test为空，则说明是正常调用页面；否则是获取页面的，则不需要再继续。

try {
System.out.println("*****begin get html*****");
String urlString;
if (requestQuery == null){
urlString = requestUrl + "?test=true";
}else{
urlString = requestUrl + "?test=true&" + requestQuery;
}
URL url = new URL(urlString);
URLConnection con = url.openConnection();
Enumeration enu1= req.getHeaderNames();
while (enu1.hasMoreElements()){
String headerName = (String)enu1.nextElement();
String headerValue = req.getHeader(headerName);
con.addRequestProperty(headerName, headerValue);
}
InputStream in = con.getInputStream();
// buffer the input to increase performance
in = new BufferedInputStream(in);
// chain the InputStream to a Reader
Reader r = new InputStreamReader(in);
int c;
while ((c = r.read( )) != -1) {
System.out.print((char) c);
}

}
catch (MalformedURLException ex) {
System.err.println(ex);
}
System.out.println("*****end get html*****");

}

System.out.println("###########end watch filter###################");

chain.doFilter(request, response);

}