请教vector中的begin()的返回值

[Dic4000]

有一程序片段:
vector<int> n;
for(int i=1;i<=100;i++) n.push_back(i);

请问:
1:n.beging()和n.end()的返回值是什么类型?
2:为什么用cout<<n.begin();语句出错?怎样才能打印出n.begin()的值?

[晨星]

（1）只能告诉你返回vector<int>::iterator类型，而这个类型的具体定义，可能随不同的库实现而不同；

（2）打印一个iterator干嘛啊？你是不是想打印：*n.begin()啊？

[benh]

1 vector<int>::iterator 类型。
2 *n.begin();

[jixingzhong]

begin
Syntax:
#include <vector>
iterator begin();
const_iterator begin() const;

The function begin() returns an iterator to the first element of the vector. begin() should run in constant time.

For example, the following code uses begin() to initialize an iterator that is used to traverse a list:

// Create a list of characters
list<char> charList;
for( int i=0; i < 10; i++ ) {
charList.push_front( i + 65 );
}
// Display the list
list<char>::iterator theIterator;
for( theIterator = charList.begin(); theIterator != charList.end(); theIterator++ ) {
cout << *theIterator;
}

Related topics:
end
rbegin
rend

[jixingzhong]

#include <vector>
iterator end();
const_iterator end() const;

The end() function returns an iterator just past the end of the vector.

Note that before you can access the last element of the vector using an iterator that you get from a call to end(), you'll have to decrement the iterator first. This is because end() doesn't point to the end of the vector; it points just past the end of the vector.

[jixingzhong]

返回的都是 迭代器（你可以理解为指针），
输出的应当是 迭代器 指向的内容：

*n.begin() *n.end()

[云梦谭]

1:n.beging()和n.end()的返回值是什么类型?
返回迭代器,注意end()返回的并不是存储最后一个元素的迭代器,而是存储最后元素迭代器的后一个,也就是说end()-1才是最后一个元素所在迭代器
2:为什么用cout<<n.begin();语句出错?怎样才能打印出n.begin()的值?
在这情况下用cout << *(n.begin());就可以了,迭代器的使用和指针很相似

[Torrice]

看看 STL