程序启动时,如何隐藏窗口

[lizhengqin]

我用C#写了一个简单软件,现在我想启动它的时候,让它隐藏到窗口的右下角,点击窗口右下角的图标,在还原到屏幕窗口.

[oolongTea]

使用NotifyIcon
启动时候
this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;

双击notifyIcon
this.WindowState = FormWindowState.Normal;
this.ShowInTaskbar = true;

[lizhengqin]

上面的代码放到哪里去,哪个事件中?

[VirtualDesktop]

NotifyIcon 是一个控件,兄弟~

[mrluoluo]

private void notifyIcon1_MouseDoubleClick(object sender, MouseEventArgs e)
{
this.Show();
this.WindowState = FormWindowState.Normal;
}


void Form1_SizeChanged(object sender, System.EventArgs e)
{
if (this.WindowState == FormWindowState.Minimized)
this.Hide();
}

[lizhengqin]

private void notifyIcon1_MouseDown(object sender, System.Windows.Forms.MouseEventArgs e)
{
this.WindowState = FormWindowState.Normal;
this.ShowInTaskbar = true;

}


不知道这段代码放在哪里?
this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;

[mrluoluo]

添加一个notifyIcon控件,设置好Icon,默认是没有的,不会显示
双击,就出来一个事件
如果想窗口在的时候,状态栏不显示,那就默认visible为false,最小化后,改为true,双击后,又为false

[lizhengqin]

现在是隐藏,但是没有隐藏到窗口右下角,不知道隐藏到什么地方去了,找不出来!

[thoughter]

Form1_Load
?

[mrluoluo]

Form1_Load时设置hide()无效!

[thoughter]

设的是WindowState...
******
要给notifyIcon1设置个icon才会显示出来

[mrluoluo]

private void notifyIcon1_MouseDoubleClick(object sender, MouseEventArgs e)
{
this.Show();
this.WindowState = FormWindowState.Normal;
this.notifyIcon1.Visible = false;
}


void Form1_SizeChanged(object sender, System.EventArgs e)//添加一个事件
{
if (this.WindowState == FormWindowState.Minimized)
{
this.notifyIcon1.Visible = true;
this.Hide();
}
}

[lizhengqin]

谢谢各位帮忙!问题已解决!

[ASDC001]

那结贴啊