怎样将Hbitmap图像垂直翻转(左右翻转也行)

[y22ang_cn]

HBITMAP m_hbmp;左右翻转也行

[Kudeet]

用GDI+的Transform转换

[y22ang_cn]

能给个例子吗?

[Kudeet]

MSDN上有现成的：
Point destinationPoints[] = {
Point(200, 20), // destination for upper-left point of original
Point(110, 100), // destination for upper-right point of original
Point(250, 30)}; // destination for lower-left point of original

Image image(L"Stripes.bmp");

// Draw the image unaltered with its upper-left corner at (0, 0).
graphics.DrawImage(&image, 0, 0);

// Draw the image mapped to the parallelogram.
graphics.DrawImage(&image, destinationPoints, 3);

[lixiaosan]

http://www.yesky.com/282/1772782_1.shtml

[y22ang_cn]

自己解决
得到图象的数据流 char *scr
char temp = new char [4096]
for(int i =0 ; i <bmp.height/2 ;i++)
{
memcpy(temp,scr+i*bmp.width*bmp.count/8,bmp.width*bmp.count/8);

}

[y22ang_cn]

自己解决
得到图象的数据流 char *scr
char temp = new char [4096]
for(int i =0 ; i <bmp.height/2 ;i++)
{
memcpy(temp,scr+i*bmp.width*bmp.count/8,bmp.width*bmp.count/8);
memcpy(scr+i*bmp.width*bmp.count/8,scr+(bmp.height-1)*bmp.width*bmp.count/8,bmp.width*bmp.count/8);
memcpy(scr+(bmp.height-1)*bmp.width*bmp.count/8,temp,bmp.width*bmp.count/8);
}