C:linked list

[avonuts]

#include<stdio.h>
#include<stdlib.h>

struct IntNode
{
int data;
struct IntNode *next;
};

typedef struct IntNode intNode;

int main()
{
intNode *node1 = NULL , *node2 = NULL , *node3 = NULL;
node1=(intNode *)malloc(sizeof(intNode));

node1->data = 1;
node1->next = node2;

node2->data = 2;
node2->next = node3;

node3->data = 3;
node3->next = NULL;

printf("%d\n",node1);

}

complied with gcc, but it displays"segmentation fault" message,could anyone tell me what is wrong with my program,thanx

[飞哥]

还是键键快!

[飞哥]

等lz也有像键键那么多裤衩的时候
估计就不会犯这样的错误了
－－－－－－－－－－－－－

[lj860603]

node1->data = 1;
node1->next = node2;

node2->data = 2;
node2->next = node3;

node3->data = 3;
node3->next = NULL;

=========================
你只是给node1申请了空间但没有给node2和node3申请空间啊。给这两个结点也申请空间就可以了。

[lj860603]

node1->data = 1;
node1->next = node2;

node2=(intNode *)malloc(sizeof(intNode));
node2->data = 2;
node2->next = node3;

node3=(intNode *)malloc(sizeof(intNode));
node3->data = 3;
node3->next = NULL;

可以了。呵呵。

[飞哥]

加油！