请高手指教!

[cstrike]

#include <iostream>
#include <vector>
#include <string>
#include <cctype>
using std::cin;
using std::vector;
using std::cout;
using std::endl;
using std::string;
int main ()
{string word;
int counter=0,i=0,n=0;
vector<string>text;
while(cin>>word)
{text.push_back(word);++counter;
}
for (i=0;i!=text.size();++i)
{text[i]=toupper(text[i]);
}
for (n=1;n%8!=0;++n)
{cout<<text[n-1]<<endl;
}
return 0;
}
程序如上,要解决的问题是读入一段文本，每个单词存为一个元素,再把每个单词转化为大写字母，输出转化后的元素.每8个一行输出.
E:\wrong\word out.cpp(18) : error C2664: 'toupper' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'int'
No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
Error executing cl.exe.
我现在有个疑问是我的输出是否正确,不清楚每8个单词输出怎么编写程序，请高手帮忙，谢谢了

[lw1a2]

toupper的参数是char

[wave_]

up

[cstrike]

请问我改怎么改正呢?麻烦帮我修改一下好吧?
还有我觉得我的程序不会输出8个单词,可能会输出8个字母,请高手指教一下

[lw1a2]

#include <iostream>
#include <vector>
#include <string>
#include <cctype>
using std::cin;
using std::vector;
using std::cout;
using std::endl;
using std::string;
int main ()
{string word;
int counter=0,i=0,n=0;
vector<string>text;
while(cin>>word)
{text.push_back(word);++counter;
}
for (i=0;i!=text.size();++i)
{transform (text[i].begin(), text[i].end(), //source
text[i].begin(), //destination
toupper);
}
for (n=1;n%8!=0&&n<text.size();++n)
{cout<<text[n-1]<<endl;
}
system("pause");
return 0;
}

[mstlq]

lw1a2(一刀 CSDN的等级，只和上网时间有关)
关于处理单词的的方法是对的，不过输出部分有点小问题，修正如下
#include <iostream>
#include <vector>
#include <string>
#include <cctype>
#include <algorithm>
#include <functional>


using std::cin;
using std::vector;
using std::cout;
using std::endl;
using std::string;
int main ()
{string word;
int counter=0,i=0,n=0;
vector<string>text;
while(cin>>word)
{text.push_back(word);++counter;
}
for (i=0;i!=text.size();++i)
{transform(text[i].begin(), text[i].end(), //source
text[i].begin(), //destination
toupper);
}
for (n=0;n<text.size();++n)
{cout<<text[n]<<" ";
if (n%8==7)
cout<<endl;
}
system("pause");
return 0;
}

————————————————————————
在g++中通过编译（vc6不可）

输入
jsldk sd0ioj psdo8r psd0fu npsoer8 pdoisaru psdoiru ;eouf pa9sdd ol9asdy lasfdi7
oasidy asdhg8ww asldiuddf lasidyuaaa aosidywewew asod8yssss （回车）
^Z（回车）

输出

JSLDK SD0IOJ PSDO8R PSD0FU NPSOER8 PDOISARU PSDOIRU ;EOUF
PA9SDD OL9ASDY LASFDI7 OASIDY ASDHG8WW ASLDIUDDF LASIDYUAAA AOSIDYWEWEW
ASOD8YSSSS 请按任意键继续. . .

达到了楼主的要求……

[mstlq]

vc6可用版本……
不过不知道为什么要连续输入两次^Z（ctrl+z 然后回车），才能结束输入……
ps：楼主给的分也太少了吧？严重打击某些朋友的积极性……

#include <iostream>
#include <vector>
#include <string>
#include <cctype>
#include <algorithm>
//#include <functional>


using std::cin;
using std::vector;
using std::cout;
using std::endl;
using std::string;

int main ()
{string word;
int counter=0,i=0,n=0;
vector<string>text;
while(cin>>word)
{text.push_back(word);++counter;
}
char *c;
for (i=0;i!=text.size();++i)
{for(c=text[i].begin(); c!=text[i].end();c++)
*c=toupper(*c);
}
for (n=0;n<text.size();++n)
{cout<<text[n]<<" ";
if (n%8==7)
cout<<endl;
}
system("pause");
return 0;
}