求算法
对div循环。当tp=1时,按dt查找,将月份和年份相同的日期的amt相加;当tp=2时,将月份和年份相同的p相加。麻烦高手帮忙了。谢谢了先!
<div dt="2000-03-10" tp="1" amt="0.0555" p="1" />
<div dt="2000-06-16" tp="1" amt="0.0776" p="3" />
<div dt="2000-09-15" tp="1" amt="0.0712" p="2" />
<div dt="2000-12-15" tp="1" amt="0.0862" p="3" />
<div dt="2000-12-15" tp="2" amt="1.005" p="5" />
<div dt="2001-03-16" tp="1" amt="0.0579" p="4" />
<div dt="2001-06-15" tp="1" amt="0.0651" p="4" />
<div dt="2001-09-20" tp="1" amt="0.0629" p="3" />
<div dt="2001-09-20" tp="2" amt="0.352" p="5" />
<div dt="2001-12-21" tp="2" amt="0.019" p="3" />
<div dt="2001-12-21" tp="1" amt="0.0553" p="2" />
<div dt="2002-03-15" tp="1" amt="0.0414" p="1" />
<div dt="2002-06-14" tp="1" amt="0.0517" p="5" />
<div dt="2002-09-13" tp="1" amt="0.0496" p="3" />
<div dt="2002-12-20" tp="1" amt="0.054" p="2" />
<div dt="2003-03-14" tp="1" amt="0.031" p="3" />
<div dt="2003-06-13" tp="1" amt="0.0335" p="3" />
<div dt="2003-09-12" tp="1" amt="0.0316" p="4" />
<div dt="2003-12-19" tp="1" amt="0.0522" p="1" />
<div dt="2004-03-12" tp="1" amt="0.0274" p="1" />
<div dt="2004-06-14" tp="1" amt="0.0411" p="2" />
<div dt="2004-09-10" tp="1" amt="0.0397" p="2" />
<div dt="2004-12-17" tp="1" amt="0.0789" p="2" />
<div dt="2004-12-17" tp="2" amt="0.648" p="3" />