页面载入之后，向2个地方请求数据的AJAX效果如何实现？

[jxyuhua]

我想在页面载入后，自动向2个WEB SERVICE请求数据，然后显示在网页上，现在请求一个的已经实现，但是当请求2个时，就会出现错误，只显示一个结果，这两个结果都是对的，但是就是不返回。

<script language="javascript" type="text/javascript">
window.onload = function()
{
http.open('get', "<?php echo HTTP_URL . 'ebaysearch2.php?query=' . urlencode($Title) . '&MaxResults=1&outputtype=javascript';?>");
http.onreadystatechange = handleEbayStoreResponse;
http.send(null);

http.open('get', "<?php echo HTTP_URL . 'yahoosearch.php?query=' . urlencode($Title) . '&results=1&outputtype=javascript';?>");
http.onreadystatechange = handleYahooStoreResponse;
http.send(null);
}

function handleYahooStoreResponse() {
if(http.readyState == 4){
var response = http.responseText;
var store = document.getElementById('yahoostore');
store.innerHTML = response;
}
}

function handleEbayStoreResponse() {
if(http.readyState == 4){
var response = http.responseText;
var store = document.getElementById('ebaystore');
store.innerHTML = response;
}
}
</script>

只有最后的一个结果显示出来，上面那个没有显示，而且第一个的http.readyState是1，不是4，但是如果直接运行ebaysearch2.php所指向的URL是可以返回数据的，为什么呢？

请高手帮忙。

[懒得去死]

<script language="javascript" type="text/javascript">
window.onload = function()
{
http.open('get', "<?php echo HTTP_URL . 'ebaysearch2.php?query=' . urlencode($Title) . '&MaxResults=1&outputtype=javascript';?>");
http.onreadystatechange = handleEbayStoreResponse;
http.send(null);

http.open('get', "<?php echo HTTP_URL . 'yahoosearch.php?query=' . urlencode($Title) . '&results=1&outputtype=javascript';?>");
http.onreadystatechange = handleYahooStoreResponse;
http.send(null);
}

function handleYahooStoreResponse() {
if(http.readyState == 4){
var response = http.responseText;
var store = document.getElementById('yahoostore');
store.innerHTML = response;
var store = document.getElementById('ebaystore');
store.innerHTML = store.innerHTML+response;
}
}
}

</script>

[懒得去死]

?
<script language="javascript" type="text/javascript">
window.onload = function()
{
http.open('get', "<?php echo HTTP_URL . 'ebaysearch2.php?query=' . urlencode($Title) . '&MaxResults=1&outputtype=javascript';?>");
http.onreadystatechange = handleResponse;
http.send(null);

http.open('get', "<?php echo HTTP_URL . 'yahoosearch.php?query=' . urlencode($Title) . '&results=1&outputtype=javascript';?>");
http.onreadystatechange = handleResponse;
http.send(null);
}

function handleResponse() {
if(http.readyState == 4){
var response = http.responseText;
var store = document.getElementById('yahoostore');
store.innerHTML = response;
var store = document.getElementById('ebaystore');
store.innerHTML = store.innerHTML+response;
}
}
}

</script>

[北京饼干]

open的时候有最后一个参数试着设置成false，同步传输就可以了

[xuzuning]

把http对象改成局部的就可以了

[jxyuhua]

我用了2个对象来处理它，现在是可以了，但觉得太不简洁。