如何使用regexp来进行正则表达式的匹配？

[escapestar]

如何使用regexp来进行正则表达式的匹配？
下面这个程序有何不妥，请各位打下指正：
#define INIT register char *sp=instring;
#define GETC() (*sp++)
#define PEEKC() (*sp)
#define UNGETC(c) (--sp)
#define RETURN(c) return;
#define ERROR(c) regerr()
#include <stdio.h>
#include <regexp.h>
main()
{
char expbuf[10];
char linebuf[80];
strcpy(expbuf,"^[0-9]*$");
compile((char *)0,expbuf,&expbuf[sizeof(expbuf)],'\0');
for (;;)
{
printf("please input a string:\n");
scanf("%s\n",linebuf);
if (step(linebuf,expbuf))
{
printf("success!\n");
}
else
printf("failed!\n");
}
}

编译时提示regerr未定义，不知何故？希望各位大虾能以例程解答
请发email至[e-mail],多谢！

[solar]

also try this example modified from your code. it works on linux(egcs) and solaris(gcc)
-----------------------------------------------
#include <stdio.h>
#include <regex.h>
main()
{
regex_t re;
char *expbuf="^[0-9]*$";
char linebuf[80];
regmatch_t pmatch[16];

regcomp(&re,expbuf,0);
for (;;){
printf("please input a string:\n");
scanf("%s",linebuf);
if(0 == regexec(&re, linebuf, 16,pmatch,0))
printf("success!\n");
else
printf("failed!\n");
}
}

[solar]

not regerr,but regerror!