scanf()多个占位符之间到底可不可以加东西?

debug1101 2014-10-16 10:56:28
最近在看C 语言时,有关scanf()函数发现一个问题:一般我们用键盘输入两个整数(十进制)时可以表达为(部分代码):
int a,b;
scanf("%d %d",&a,&b);
printf("%d,%d",a,b);
问题是当我在两个%d之间加一个逗号“,”(或者别的字母数字之类的),输出结果会是什么样子的??
我也查了《C primer plus》中讲到这一点中间加入是逗号时,但是我用VC6.0运行结果和书上不一样,是不是编译器的原因?
如果占位符之间加入的是字母数字时,运行结果又是什么样子的?
第一次发帖啊,求大神们详细分析一下,谢谢了!
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ForestDB 2014-10-17
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非格式化的字符应该对应的出现于输入流中,即 scanf("%d,%d", &a, &b); 那么输入的时候就应该输入 1[b],[/b]2
li4c 2014-10-17
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尽量不要把多个输入写在一个scanf里面,因为别人用你的程序的时候,不知道你用的是逗号还是空格。所以你还是分开写计较好,如果你需要多个输入,可以把scanf放在一个循环里面
debug1101 2014-10-17
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恩,懂了,不知道为什么我用VC6.0运行后,非运算控制符后后显示:烫烫烫烫烫烫烫。。。
勤奋的小游侠 2014-10-17
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原样输入。scanf中间加了逗号,输入时也要加逗号,中间加了字母,输入时也要加。
707wk 2014-10-17
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按格式输入。。。
百曉生 2014-10-17
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引用 3 楼 duoyidu981617019 的回复:
恩,懂了,不知道为什么我用VC6.0运行后,非运算控制符后后显示:烫烫烫烫烫烫烫。。。
检查检查,看是哪里不对了 建议不要使用VC6了,太老了,推荐dev c++、c-free、vs2010及以上版本等
赵4老师 2014-10-17
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Format Specification Fields: scanf and wscanf Functions A format specification has the following form: %
  • [width] [{h | l | I64 | L}]type The format argument specifies the interpretation of the input and can contain one or more of the following: White-space characters: blank (' '); tab ('\t'); or newline ('\n'). A white-space character causes scanf to read, but not store, all consecutive white-space characters in the input up to the next non–white-space character. One white-space character in the format matches any number (including 0) and combination of white-space characters in the input. Non–white-space characters, except for the percent sign (%). A non–white-space character causes scanf to read, but not store, a matching non–white-space character. If the next character in stdin does not match, scanf terminates. Format specifications, introduced by the percent sign (%). A format specification causes scanf to read and convert characters in the input into values of a specified type. The value is assigned to an argument in the argument list. The format is read from left to right. Characters outside format specifications are expected to match the sequence of characters in stdin; the matching characters in stdin are scanned but not stored. If a character in stdin conflicts with the format specification, scanf terminates, and the character is left in stdin as if it had not been read. When the first format specification is encountered, the value of the first input field is converted according to this specification and stored in the location that is specified by the first argument. The second format specification causes the second input field to be converted and stored in the second argument, and so on through the end of the format string. An input field is defined as all characters up to the first white-space character (space, tab, or newline), or up to the first character that cannot be converted according to the format specification, or until the field width (if specified) is reached. If there are too many arguments for the given specifications, the extra arguments are evaluated but ignored. The results are unpredictable if there are not enough arguments for the format specification. Each field of the format specification is a single character or a number signifying a particular format option. The type character, which appears after the last optional format field, determines whether the input field is interpreted as a character, a string, or a number. The simplest format specification contains only the percent sign and a type character (for example, %s). If a percent sign (%) is followed by a character that has no meaning as a format-control character, that character and the following characters (up to the next percent sign) are treated as an ordinary sequence of characters, that is, a sequence of characters that must match the input. For example, to specify that a percent-sign character is to be input, use %%. An asterisk (*) following the percent sign suppresses assignment of the next input field, which is interpreted as a field of the specified type. The field is scanned but not stored.
百曉生 2014-10-16
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