怎么把 指针b的指向的地址作为值 放到指针a指向的地址里？

[耐心是关键]

char* a=(char*)malloc(10);

char* b="ddd";

//怎么写？

printf("%s\n", a);//能打印出b的地址

[kkk2017]

char* a=(char*)malloc(10); char* b="ddd"; *(int*)a=(int)b; printf("0x%x\n", *(int*)a);//能打印出b的地址

[derekrose]

http://www.cplusplus.com/reference/cstring/memset/

[majunyangyang]

中间加上： long lbPos = (long)&(*b); unsigned short wRemain; a[0] = '0'; a[1] = 'x'; for(unsigned short wTemp = 0; wTemp < 8; wTemp++) { wRemain = lbPos % 16; lbPos = lbPos / 16; if (wRemain < 10) { a[9 - wTemp] = '0' + wRemain; } else { a[9 - wTemp] = 'a' + wRemain - 10; } } 不知道楼主是不是这个意思？

[耐心是关键]

好像是这个意思，1楼的答案不错，谢谢哈