关于C的一个小问题

[qq_40571620]

C语言中空格占多少字符？

[will热爱]

1个 。

[Painot]

空格占 1个字符

[自信男孩]

建议查阅ascii，空格占1个字符，但是tab,'\t'可能是4个空格或者8个空格（可以配置的），但是'\t'就是一个字符

[似缘非缘]

#include <stdio.h>
int main()
{
    printf("size of char: %ld byte(s)\n", sizeof(char));
    const char space = ' ';
    printf("size of one space: %ld byte(s)\n", sizeof(space));
    int char_num_per_space = sizeof(space) / sizeof(char);
    printf("amount of char in one space: %d\n", char_num_per_space);
}

Output:

[赵4老师]

不要迷信书、考题、老师、回帖； 要迷信CPU、编译器、调试器、运行结果。 并请结合“盲人摸太阳”和“驾船出海时一定只带一个指南针。”加以理解。 任何理论、权威、传说、真理、标准、解释、想象、知识……都比不上摆在眼前的事实！

[赵4老师]

空格多了！ 参考下面：

#pragma comment(lib,"gdi32")
#include <windows.h>
#include <stdio.h>

int main() {
    const DWORD uWidth = 18 + 17 * 256, uHeight = 18 + 17 * 128;

    PBITMAPINFO pbmi = (PBITMAPINFO) LocalAlloc (LPTR, sizeof (BITMAPINFOHEADER) + sizeof (RGBQUAD) * 2);
    pbmi->bmiHeader.biSize = sizeof (BITMAPINFOHEADER);
    pbmi->bmiHeader.biWidth = uWidth;
    pbmi->bmiHeader.biHeight = uHeight;
    pbmi->bmiHeader.biPlanes = 1;
    pbmi->bmiHeader.biBitCount = 1;
    pbmi->bmiHeader.biSizeImage = ((uWidth + 31) & ~31) / 8 * uHeight;
    pbmi->bmiColors[0].rgbBlue = 0;
    pbmi->bmiColors[0].rgbGreen = 0;
    pbmi->bmiColors[0].rgbRed = 0;
    pbmi->bmiColors[1].rgbBlue = 255;
    pbmi->bmiColors[1].rgbGreen = 255;
    pbmi->bmiColors[1].rgbRed = 255;

    HDC hDC = CreateCompatibleDC (0);
    void * pvBits;
    HBITMAP hBitmap = CreateDIBSection (hDC, pbmi, 0, &pvBits, NULL, 0);
    SelectObject (hDC, hBitmap);
    HFONT hFont = CreateFont (16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, "宋体");
//  HFONT hFont = CreateFont (16, 0, 0, 0, 0, 0, 0, 0, SHIFTJIS_CHARSET, 0, 0, 0, 0, "宋体");
    SelectObject (hDC, hFont);
    BitBlt (hDC, 0, 0, uWidth, uHeight, NULL, 0, 0, WHITENESS);

    char c[4];
    int i, j;
    for (i = 128; i < 256; i++) {
        sprintf (c, "%02X", i);
        TextOut (hDC, 1, (i - 127) * 17 + 1, c, 2);
    }
    for (j = 0; j < 256; j++) {
        sprintf (c, "%02X", j);
        TextOut (hDC, (j + 1)* 17 + 1, 1, c, 2);
    }
    for (i = 128; i < 256; i++) {
        for (j = 0; j < 256; j++) {
            c[0] = (char) i;
            c[1] = (char) j;
            TextOut (hDC, (j + 1) * 17 + 1, (i - 127) * 17 + 1, c, 2);
        }
    }
    for (i = 0; i < 130; i++) {
        MoveToEx (hDC, 0, i * 17, NULL);
        LineTo (hDC, uWidth, i * 17);
    }
    for (j = 0; j < 258; j++) {
        MoveToEx (hDC, j * 17, 0, NULL);
        LineTo (hDC, j * 17, uHeight);
    }

    BITMAPFILEHEADER bmfh;
    bmfh.bfType = *(PWORD) "BM";
    bmfh.bfReserved1 = 0;
    bmfh.bfReserved2 = 0;
    bmfh.bfOffBits = sizeof (BITMAPFILEHEADER) + sizeof (BITMAPINFOHEADER) + sizeof (RGBQUAD) * 2;
    bmfh.bfSize = bmfh.bfOffBits + pbmi->bmiHeader.biSizeImage;

    HANDLE hFile = CreateFile ("goal.bmp", GENERIC_WRITE, 0, 0, CREATE_ALWAYS, 0, 0);
    if (hFile != INVALID_HANDLE_VALUE) {
        DWORD dwWritten;
        WriteFile (hFile, &bmfh, sizeof (BITMAPFILEHEADER), &dwWritten, NULL);
        WriteFile (hFile, pbmi, sizeof (BITMAPINFOHEADER) + sizeof (RGBQUAD) * 2, &dwWritten, NULL);
        WriteFile (hFile, pvBits, pbmi->bmiHeader.biSizeImage, &dwWritten, NULL);

        CloseHandle (hFile);
    }

    DeleteObject (hFont);
    DeleteObject (hBitmap);
    DeleteDC (hDC);
    LocalFree (pbmi);

    return 0;
}

生成的goal.bmp

[yqchilde]

空格占 1个字符

[hamity]

空格应该就是占1个字符吧，我也是新手

[开源学开源]

我觉得像这中情况，自己编程可以更快得到答案！sizeof

[陪妳看星星]

看看ASCII码就知道，空格符码值是32，同'a', 'b', 'c'一样属于可打印字符。它本身是一个字符，占用的字节数是1。 如果哪天C标准规定char型值是2个字节或4个字节，那空格符就占2个或4个字节，但它本身还是一个字符。