strcpy该怎么用

[lingkeylbh]

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char *argv[])
{
char *dst,*src;
src = "hello,strcpy";
strcpy(dst,src);
//dst = src;
printf("%s %s\n",src,dst);
system("PAUSE");
return 0;
}
我不知道哪里错了，谁指点一下啊

[DonaldKnuth]

//你的dst没有分配内存
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char *argv[])
{
char dst[20], *src;
src = "hello,strcpy";
strcpy(dst,src);

printf("%s %s\n",src,dst);
system("PAUSE");
return 0;
}

[iamcaicainiao]

//或者这样。

#include <cstdlib>
#include <iostream>

#include <string.h>
using namespace std;
int main(int argc, char *argv[])
{
char *dst,*src;
dst = new char(strlen(src)+1);
src = "hello,strcpy";
strcpy(dst,src);
//dst = src;
printf("%s %s\n",src,dst);


system("PAUSE");
return EXIT_SUCCESS;

}

[todototry]

strcpy(dst,src);
================
dst指针所指向的内存段需足够尺寸存放src字符串，需分配好内存，数组堆内存