关于子网计算,在线等待

[wanghai]

You are the administrator of a Windows 2000 network. You want to create a DHCP scope for
the 192.166.1.32/28 subnet. The computers on this subnet are running Windows 95,
Windows 98, and Windows 2000. You also have two UNIX computers on this subnet that
will have static IP addresses. These UNIX computers will be assigned the two highest
available IP addresses on the subnet. The subnet's default gateway will be assigned the lowest
available IP address on the subnet. The scope should only include the available addresses.
Which scope should you create on your DHCP server for this subnet?
A. 192.168.1.34 - 192.168.1.46
B. 192.168.1.34 - 192,168.1.44
C. 192.168.1.33 - 192168.1.45
D. 192.168.1.34 - 192.168.1.61
E. 192.168.1.33 - 192.168.1.60

[wanghai]

给出详细解答

[xuying]

子网192.168.1.32，掩码255.255.255.240，所以ip范围是192.168.1.33到192.168.1.46。去掉两个unix占据的最高位45,46和网关的最低位33，所以可用的范围是192.168.1.34 - 192.168.1.44。

所以选B

[wanghai]

和偶想的一样，给分