跪求！

[mfj1983]

#include <stdio.h>
static void strcpy_pos(char *dst, char *src, unsigned char pos, unsigned char count);
void main()
{
char *first;
char second［１０］;

first="004999010640000";

strcpy_pos(second,first,9,6);
printf("%s",second);
}

static void strcpy_pos(char *dst, char *src, unsigned char pos, unsigned char count)
{
unsigned char i;
for (i=0 ; i< count ; i++)
dst[i] = src[i+pos];
dst[i] = '\0';
}

运行是正确的，而
#include <stdio.h>
static void strcpy_pos(char *dst, char *src, unsigned char pos, unsigned char count);
void main()
{
char *first;
char *second;／／不同处

first="004999010640000";

strcpy_pos(second,first,9,6);
printf("%s",second);
}

static void strcpy_pos(char *dst, char *src, unsigned char pos, unsigned char count)
{
unsigned char i;
for (i=0 ; i< count ; i++)
dst[i] = src[i+pos];
dst[i] = '\0';
}

为什么会有错误呢？

[expter]

因为char *second;没分配空间
char *first;
char *second;／／不同处

second=new char [10];
就可以了

[celftj]

第二个是错误的,指针要分配内存再往指针指向的内存写东东.

第一个只是把另一个指针值给了first