想用sprintf写成05应该怎么写?

[lockhall]

#include "stdio.h"
#include "stdlib.h"

int main()
{
int i = 5;
char *buf;
buf = (char *)malloc(10*sizeof(10));
sprintf(buf, "%d", i);
printf("%s",buf);
getchar();
return 0;
}

我想buf里是"02",而不是2,该怎么改/?

[celftj]

sprintf(buf, "%.2d", i);

试试

[celftj]

CString szTemp;

szTemp.Format("%.2d", time.wMonth);
我试过是行的

[believefym]

sprintf(buf, "%02d", i);

[lb_hit]

好奇问一句：
buf = (char *)malloc(10*sizeof(10));
~~~~~~~~~~~~~这是干什么？

[lockhall]

手误了

应该是buf = (char *)malloc(10*sizeof(char));
就是给buf分配内存的．

[珍惜生命远离CPP]

sprintf(buf, "%03d", i);

[fengdream]

sprintf(buf,"%02d",i);
sprintf(buf,"0%d",i);
getch();