紧急求救,大家帮帮忙。我这里有个程序。。建立两个文件,在文件中输入两个集合的元素,在将他们的交集输入到第三个文件中
#include<stdio.h>
void main( )
{
char ch, c;
FILE *fpa, *fpb, *fpc;
int n, k, count;
int i = 0, j = 0;
int a[1000];
printf("在磁盘中新建两个TXT文件,分别取名为a.txt,b.txt\n");
printf("分别在两个文件中输入两个集合的元素,输入完毕后以输入空格表示开始执行求交集.\n");
if((ch = getchar()) == ' ')
{
if((fpa = fopen( "a.txt", "r")) == NULL)
{
printf( "你在a文件中输入的为空,如果确定则按空格,若不确定请按任意键退出,重新执行文件并输入数据!");
if( ch = getchar() == ' ')
{
fpc = fopen( "c.txt", "w");
c = getchar( );
fputc(ch,fpc);
}
else printf( "关闭程序重新输入\n");
}
if((fpb = fopen( "b.txt", "r")) == NULL)
{
printf( "你在b文件中输入的为空,如果确定则按空格,若不确定请按任意键退出,重新执行文件并输入数据!");
if( ch = getchar() == ' ')
{
fpc = fopen( "c.txt", "w");
c = getchar( );
fputc(ch,fpc);
}
else printf( "关闭程序重新输入\n");
}
if(fclose(fpb))
{
printf( "不能关闭次文件\n");
exit(0);
}
while( !feof(fpa))
{
fscanf( fpa, "%d", &n);
while( !feof(fpb))
{
fpb = fopen( "b.txt", "r");
fscanf( fpb, "%d", &k);
if( n == k)
{
/*fopen( "c.txt","w");
fpc = fopen( "c.txt","w");
sprintf(fpc, "%d", &n);*/
a[i] = n;
i ++ ;
}
count = i;
}
if(fclose(fpb))
{
printf( "不能关闭次文件\n");
exit(0);
}
}
if(fclose(fpa))
{
printf( "不能关闭次文件\n");
exit(0);
}
for( i = 0; i <= count; i ++ )
{
for( j = i + 1; j <= count; j ++ )
{
if(a[i] == a[j])
{
for(; j <= count; j ++)
{
a[j] = a[j+1];
count -- ;
}
}
}
}
fpc = fopen( "c.txt", "w");
for( i = 0; i <= count; i ++ )
{
fprintf(fpc, "%d", a[i]);
}
}
}