结构体语法问题,请指教.谢谢!!

[James_ht]

typedef struct _T_B
{
int received[256];
}TB;
typedef struct _T_ShiftService
{

// TB receivedTable[0x10];
TB *receivedTable;
}T_ShiftService;
T_ShiftService ServiceBuf[10];

void Test()
{
TB *receivedTable = NULL;
ServiceBuf[0].receivedTable = receivedTable;
// ServiceBuf[0]->receivedTable = receivedTable; 和上面有什么不同. 解译一下语法错误的原因.
}

[p0303230]

ServiceBuf[0].receivedTable = receivedTable;//  这里的ServiceBuf[0]是对象
ServiceBuf[0]->receivedTable = receivedTable; ->要用指针  显然ServiceBuf[0]不是 换成&ServiceBuf[0]也许可以 

[lanmuyi]

ServiceBuf[0]是T_ShiftService类型，就要用ServiceBuf[0].使用结构中的变量；
如果ServiceBuf[0]是T_ShiftService *类型，就要用ServiceBuf[0]->

[sun420]

指针类型用->调用结构成员
对象类型用.调用结构成员

[liyuzhu_1984]

[Quote=引用 1 楼 p0303230 的回复:]
C/C++ codeServiceBuf[0].receivedTable = receivedTable;// 这里的ServiceBuf[0]是对象
ServiceBuf[0]->receivedTable = receivedTable; ->要用指针 显然ServiceBuf[0]不是 换成&ServiceBuf[0]也许可以
[/Quote]

[ZiSheng]

显然楼主把两个指针搞混了，一个是结构体指针，一个是结构体成员是个指针，只有是结构体指针时，才能用－>，和你的成员是指针与否无关

[qmm161]

[Quote=引用 3 楼 sun420 的回复:]
指针类型用->调用结构成员
对象类型用.调用结构成员
[/Quote]

[chenzhp]

指针类型用->调用结构成员
对象类型用.调用结构成员