如何随机产生26字母，计算个数并在指定两个字母单词出现时停止？

[Y198895]

作业要求我们计算随机产生的字母个数，并在当出现at,is,he,up,on,we时停止并输出字母个数~~~~~·提示是根据1到26的数字来选择字母~~~~帮帮忙~~~不懂~~~

[baihacker]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define MAKE_WORD(a, b) (((a)-'a')*26+(b)-'a')
int main()
{
	int		a, b;
	int		dest[]={MAKE_WORD('a','t'), MAKE_WORD('i','s'), MAKE_WORD('h','e'),
					MAKE_WORD('u','p'),MAKE_WORD('o','n'), MAKE_WORD('w','e')};
	char*	stb[]={"at","is","he","up","on","we"};
	int		i, flag = 1, n = 0;

	srand(time(NULL));
	while (flag)
	{
		a = rand()%26, b = rand()%26;
		++n;
		printf("%c%c\n", (a&0xff)+'a', (b&0xff)+'a');
		for (int i = 0, it = a*26+b; i < sizeof(dest)/sizeof(dest[0]); ++i)
			if (dest[i] == it)
			{
				flag = 0;
				break;
			}
	}
	printf("%d\n", n);
	return 0;
}

[iwantfat]

#include "stdafx.h"
#include <stdlib.h>
#include <time.h>

#include <stdio.h>

/*65-90 97-122*/

int Generate()
{
static int num = 0;
int rand1;
int rand2;
srand( (unsigned)time( NULL ) );
while(1)
{
rand1 = ((int) rand() % (int) 26 );
num++;
rand2 = ((int) rand() % (int) 26 );
num++;
if((rand1 == 'a'-97 ) && (rand2 == 't'-97)) //其他组合类似
{
printf("%c%c",rand1+97,rand2+97);
break;
}
}

return num;

}

int _tmain(int argc, _TCHAR* argv[])
{
int i =Generate();
printf("%d",i);
return 0;
}

-----------------------------vs2005

[Erorr]

#include <stdlib.h>
#include <iostream>
#include <time.h>

using namespace std;

int main()
{
	int i = 0;
	char pre = ' ';
	char now = ' ';

	int n = 0;
	srand( (unsigned)time( NULL ) );

	while (1)
	{
		i = rand() % 26;

		pre = now;
		now = (char) (i + 97);
		printf("%c", now);

		if ((pre == 'a' && now == 't')
			|| (pre == 'i' && now == 's')
			|| (pre == 'h' && now == 'e')
			|| (pre == 'u' && now == 'p')
			|| (pre == 'o' && now == 'n')
			|| (pre == 'w' && now == 'e'))
		{
			break;
		}

		n++;
	}

	printf("\ncharacters: %d\n", n);
	
	return 0;
}

[Erorr]

楼上两位只能输出偶数吧

[iwantfat]

4楼说的很对，考虑不周全

#include "stdafx.h"
#include <stdlib.h>
#include <time.h>

#include "string.h"
#include <stdio.h>

/*65-90 97-122*/

int Generate()
{
static int num = 0;
static int rand1;
static int rand2;
srand( (unsigned)time( NULL ) );
while(1)
{
rand1 = ((int) rand() % (int) 26 );
num++;

if(rand1 == 'a'-97 )
{
rand2 =rand1;
continue;
}
if((rand1 == 't'-97)) //其他组合类似
{
printf("%c%c",rand2+97,rand1+97);
break;
}

}
return num;
}

void main()
{
int m = Generate();
printf("\n%d",m);
}

[rushman]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define RANDCHAR (rand() % 26 + 'a')
#define CHARINDEX(c) (((unsigned)(unsigned char)(c - 'a')) % 26)

void main(void){
// 查表判断 at,is,he,up,on,we
    const char flags[] = {'t', 0, 0, 0, 0, 0, 0, 'e', 's', 0, 0, 0, 0, 0, 'n', 0, 0, 0, 0, 0, 'p', 0, 'e', 0, 0, 0};
    char c, lc;
    signed count;

    srand((unsigned)time(NULL));
	printf("%d\n", CHARINDEX('b'));
    for(count = 0, c = RANDCHAR, lc = 'b'; flags[CHARINDEX(lc)] != c; lc = c, c = RANDCHAR, count++){
		if(count < 0)break;
    }
	printf("\n\nTotal : %d\n", count);
}

[UltraBejing]

我也想了解，谢谢LZ.