如何去掉字符串中的小数点？急急急！！！

[sxebcnk]

比如： 字符串 12789.56 转换为 1278956
字符串 1328.00 转换为 132800
字符串 1356.10 转换为 135610

[chlaws]

char *strtok(char *str1, char *str2);

[baihacker]

#include  <stdio.h>
char* Modify(char* str)
{
	char* curr = str, * ret = str;
	while (*curr=*str++)
		if (*curr != '.') curr++;
		return ret;
}
int main(int argc, char* argv[]) 
{ 
	char data[][32] = {"12789.56", "1328.00", "1356.10"};
	int i;
	for (i = 0; i < sizeof(data)/sizeof(data[0]); ++i)
		printf("%s\n", Modify(data[i]));
	return 0; 
} 

[野男孩]

char str[] = "12789.56";
char dst[1024] = {0};

char* p = strtok(str, ".");
while(p)
{
strcat(dst, p);
p = strtok(NULL, ".");
}

printf("dst = %s\n", dst);

[chenzhp]

#include <string.h>
#include <stdio.h>

int main(void)
{
char input[16] = "abc,d";
char *p;

/* strtok places a NULL terminator
in front of the token, if found */
p = strtok(input, ",");
if (p) printf("%s
", p);

/* A second call to strtok using a NULL
as the first parameter returns a pointer
to the character following the token */
p = strtok(NULL, ",");
if (p) printf("%s
", p);
return 0;
}

[K行天下]

#include <string.h>
#include <stdio.h>
#include <malloc.h>

char* getoutpoint(char* s)
{
    int i, j,len = strlen(s);
    char* out =malloc(len);
    for(i=0,j=0; i<len;i++)
    {
         if(*(s+i)!='.')
         {    
              out[j]= *(s+i);
              /* printf("%c\t%d\n",out[j],j); */
              j++;

         }
    }  
     out[j] = '\0';
     return out;
}
     int main()
     {
         char* p1 = getoutpoint("12789.56");
         printf("%s\n",p1);
         getch();
         free(p1);
         return 0;
         }
     

[bitxinhai]

#include<string>
#include<iostream>
using namespace std;
void main()
{
string s = "1.2356";

int i = s.find('.');
s.erase(i,i);
cout<<s<<endl;

}

[noliper]

#include <stdio.h>
#include <stlib.h>

#include <string.h>

char *p = "12345.78";
char *tmp;
char buf[100];

memset(buf,'\0',100);
tmp = strrchr(p,".");
memcpy(buf,p,tmp -p -1);
atoi(buf);

程序写错了，不过可以考虑strrchr这个函数。很简单,所以就不多写了

[飞哥]

乘以100，截取一下

[leeldy]

#include"string.h"

void qd(char *p)
{
    int i=0;
    while(p[i]!='.' && p[i]!='\0')i++;
    if(p[i]!='\0')strcpy(p+i,p+i+1);//如果字符串中没有小数点就不用去除
}

[xhd3767]

#include <string.h>
#include <iostream>
using namespace std;
int main()
{
	char* str = "1328.00";
	int temp = atoi(str);
	cout<<temp*100<<endl;

}

雁南飞的.....

[青葱岁月不可追]

/* d.c
* 如何去掉字符串中的小数点？
* 比如： 字符串 12789.56  转换为 1278956 
*        字符串  1328.00  转换为  132800 
*        字符串  1356.10  转换为  135610 
*/

#include <stdio.h>
#include <stdlib.h>

void judge_argc(int argc);
void judge_inputdata(char *pInputData);
void del_dot(char *pInputData);
void display(char *argv);

int main(int argc,char *argv[])
{
	judge_argc(argc);
	judge_inputdata(argv[1]);
	del_dot(argv[1]);
	display(argv[1]);
	
	return 0;
}

/** 
* @brief
* This function named judge_argc is used for judging the number of 
*data inputed from command line. 
*If the data is wrong,it will show an information prompts error.       
*@param  argc      the number of the command line param.      
*/ 
void judge_argc(int argc)
{
    if(argc < 2)
	{
		printf("Input Error!\nUsage:programmename data\n");
		exit(0);
	}
}

/** 
* @brief
* This function named judge_inputdata is used for judging the validity of 
*data inputed from command line. 
*If the data is wrong,it will show an information prompts error.       
*@param  pInputData      the pointer of the command line param array.      
*/  
void judge_inputdata(char *pInputData)
{
    int i;
    
    /* ASCII code：+:043  -:045  .:046  0-9:048-057  */
    for(i = 0;i < strlen(pInputData);i++)
    {
        if(((pInputData[i] >= 48) && (pInputData[i] <= 57)) || (pInputData[i] == 46))
        {
            continue;
        }
        else
        {
            if(((pInputData[i] == 43) || (pInputData[i] == 45)) && (i == 0))
            {
                continue;
            } 
            else
            {
                printf("Input Error!\n(The inputed data must be the numbers 0-9 or + - . and + - must be the first.)\n");
                exit(0);
            }        
        }        
    }  
}

/** 
* @brief
* This function named del_dot is used for delete the dot in the data.     
*@param  pInputData      the pointer of the command line param array.      
*/ 
void del_dot(char *pInputData)
{
	int i,j,k;
	int iFlag = 0;  /* the number of the dot */
	int iLen = strlen(pInputData);
	
	for(i = 0;i < iLen;i++)
	{
		if(pInputData[i] == '.')
		{
			iFlag = iFlag + 1;
			for(j = (i + 1),k = i;j < iLen;j++,k++)
			{
				pInputData[k] = pInputData[j];
			}
		}
	}
	
	if(0 != iFlag)
	{
		for(i = 0;i < iFlag;i++)
		{
			pInputData[iLen - i - 1] = '\0';
		}
	}
}

/** 
* @brief
* This function named display is used for display the processed data.     
*@param  argv      the pointer of the processed data.      
*/ 
void display(char *argv)
{
	int i;
	
	printf("The processed data is:\n");
	for(i = 0;i < strlen(argv);i++)
	{
		printf("%c",argv[i]);
	}
	printf("\n");
}

[青葱岁月不可追]

编译成功之后生成d.exe
从命令行输入：
1）
输入：
d
输出：
Input Error!
Usage:programmename data
2）
输入：
d agkja1324
输出：
Input Error!
(The inputed data must be the numbers 0-9 or + - . and + - must be the first.)
3）
输入：
d 123.12
输出：
12312
4）
输入：
d 123.12.34
输出：
1231234

[yyyapple]

void chardel(char *source, const char sub) 
{
	char *pc1, *pc2;
	int isource;
	isource= strlen(source);

	while(*source != 0)
	{
		pc1 = source;

		if(sub == *pc1)
		{
		    memmove(pc1, pc1+1, strlen(source));
		} else {
	            source++;
		}
	}
}

int main()
{
    char str[32] = "1328.00";
    chardel(str, '.');

}

chardel

[yyyapple]

lz可以给分了

[des2006]

//用stl的string，问题很简单的
#include <string>
#include <iostream>
using namespace std;
void main()
{
  std::string str1 = "12789.56";
  std::string res = str1.substr(0,str1.find(".",0,1)-1)+str1.substr(str1.find(".",0,1)+1,str1.size());
  cout<<res<<endl;//res就是你想要的东西咯
}