如何将下面的字符串转换为人民币格式的字符串

[sxebcnk]

870000 8700.00
825304 8253.04
598762 5987.62

[ouyh12345]

printf("%.02f", count / 100.0);

[K行天下]

前面加上一个 ￥

[sxebcnk]

是字符串啊，大哥！

[青葱岁月不可追]

是人民币大写吗？

[ForestDB]

char buffer[1024];
sprintf(buffer, "%.02f", count / 100.0);

[xkyx_cn]

int num = 598762;
char str[20] = {0};
sprintf(str, "￥%4.2f", (float)num / 100);

[青葱岁月不可追]

#include <stdio.h>
#include <stdlib.h>

int main()
{
	char c[10];
	char a[] = "812345";
	float data = 0;
	
	memset(c,'\0',sizeof(c));
	sprintf(c,"%.2f",(atof(a) / 100.0));
	printf("%s\n",c);
	
	data = atof(a) / 100.0;
	printf("%.2f\n",data);
	
	return 0;
}

[sxebcnk]

最好是一个函数或过程。

[sxebcnk]

各位大大给来个过程或者函数实现一下。

[xkyx_cn]

#include <stdio.h>
#include <stdlib.h>

char *float2RMB(char *buf, const float fn)
{
    if (buf == NULL)
        return NULL;

    sprintf(buf, "￥%.2f", (float)fn / 100);

    return buf;
}

int main()
{
    char c[20] = {0};
    float data = 598762;

    float2RMB(c, 598762);
    printf("%s\n", c);
    
    return 0;
}

[lwouyang]

LS各位辛苦了。

[我看你有戏]

回家做

[青葱岁月不可追]

[Quote=引用 8 楼 sxebcnk 的回复:]
最好是一个函数或过程。
[/Quote]
都已经给你贴代码了，copy出来就是个函数了……
要想进步可不能连这么easy的都让别人代劳……

[我看你有戏]

#include <stdio.h> 
#include "string.h"
void main() 
{ 
	char *strwei[] = {
		"分","角","元","拾","百","千",
			      "万","拾","百","千",
			      "亿","拾","百","千"};
		char *strcc[10] = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
		/*
		8700008700.00 
		8253048253.04 
		5987625987.62
		*/
	int *pnsz;
	int nindex=0;
	char sz_sm[20]={0};
	sprintf(sz_sm,"8253048253.04");
	pnsz = new int[strlen(sz_sm)-1];

	for(int i=strlen(sz_sm)-1;i>-1;i--)
	{
		if(sz_sm[i]=='.')
			continue;

		pnsz[nindex++] = sz_sm[i]-48;
	}

	printf("%s转化为大写数字:\n",sz_sm);
	char str[20];
	for(i=nindex-1;i>-1;i--)
	{
		sprintf(str,"%s%s",strcc[pnsz[i]],strwei[i]);
		printf("%s",str);
	}

	delete pnsz;
}
//自己在改改，有零的时候还需要改进的